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ANEK [815]
3 years ago
12

Last year Tammy had $4,500 to invest in two savings accounts. One account earns 7% simple annual interest, and the other account

earns 6% simple annual interest. At the end of the year, Tammy had earned a total of $290 in interest from the two savings accounts
Mathematics
1 answer:
kodGreya [7K]3 years ago
7 0
LOOK IT UP PLZZ I  DONT KNOW
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Write an algebric pharse for five times a number increased by nine.<br><br> i need help
trasher [3.6K]

Answer:

Step-by-step explanation:

five times a number increased by nine is

5x+9

x is the unknown number being multiplied by 5

increase= add

so add by 9

6 0
3 years ago
Can someone please help me find the range
defon

Answer:

Step-by-step explanation

4 0
3 years ago
Solve for V<br> 1 - 5V = V + 9 – 10V
denpristay [2]

Answer:

2

Step-by-step explanation:

1-5V=V+9-10V

1-5V-V-(-10V)=9

1-5V-V+10V=9

1-6V+10V=9

1+4V=9

4V=9-1

4V=8

V=8/4

V=2

7 0
3 years ago
Read 2 more answers
A vial holds 2 milliliters of pixie dust.
Alina [70]

Hi your answer would be 6 1/2 vials of pixie dust!

5 0
2 years ago
A sample of 47 observations is selected from a normal population. The sample mean is 30, and the population standard deviation i
erma4kov [3.2K]

Answer:

We accept the null hypothesis and reject  the alternate hypothesis. There is no evidence to conclude that the population mean is greater than 29. The population mean is less than or equal to 29.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 29

Sample mean, \bar{x} = 30

Sample size, n = 47

Alpha, α = 0.05

Population standard deviation, σ = 5

First, we design the null and the alternate hypothesis

H_{0}: \mu \leq 29\\H_A: \mu > 29

a) This is a one-tailed test because the alternate hypothesis is in greater than direction.

We use One-tailed z test to perform this hypothesis.

b) z_{stat} > z_{critical} , we reject the null hypothesis and accept the alternate hypothesis and if z_{stat} < z_{critical} , we accept the null hypothesis and reject  the alternate hypothesis.

c) Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

z_{stat} = \displaystyle\frac{30 - 29}{\frac{5}{\sqrt{47}} } = 1.37

d) Now, z_{critical} \text{ at 0.05 level of significance } = 1.64

Since,  

z_{stat} < z_{critical}

We accept the null hypothesis and reject  the alternate hypothesis. There is no evidence to conclude that the population mean is greater than 29. The population mean is less than or equal to 29.

e) P-value is 0.0853

On the basis of p value we again accept the null hypothesis.

5 0
3 years ago
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