Answer:
I dont have any context, but my best guess is it will be all of the above.
Answer:
68cm
Explanation:
You can solve this problem by using the momentum conservation and energy conservation. By using the conservation of the momentum you get
m: mass of the bullet
M: mass of the pendulum
v1: velocity of the bullet = 410m/s
v2: velocity of the pendulum =0m/s
v: velocity of both bullet ad pendulum joint
By replacing you can find v:
this value of v is used as the velocity of the total kinetic energy of the block of pendulum and bullet. This energy equals the potential energy for the maximum height reached by the block:
g: 9.8/s^2
h: height
By doing h the subject of the equation and replacing you obtain:
hence, the heigth is 68cm
Draw an x y axis
3 miles west is 3 miles to the left, -3
4 miles south is 4 miles down, -4
connect the the point to the origin, that side is what you are looking for
that side is also hypotenus
using Pythagorean theorem
sqrt(-4^2 + 3^2)
sqrt(25)
5
your displacement is 5
Weight = (mass) x (gravity).
It always acts downward.
On Earth, the acceleration of gravity is 9.807 m/s².
On the Moon, the acceleration of gravity is 1.623 m/s².
On Earth, the rocket's weight is (0.8kg) x (9.8 m/s²) = 7.84 newtons
On the Moon, the rocket's weight is (0.8kg) x (1.62 m/s²) = 1.3 newtons
The force of the rocket engine acts upward.
Its magnitude is 12 newtons. (From the burning chemicals.
Doesn't depend on local gravity. Same force everywhere.)
Now we have all the data we need to mash together and calculate the
answers to the question. You might choose a different method, but the
machine that I have selected to do the mashing with is Newton's 2nd law
of motion:
Net Force = (mass) x (acceleration).
Since the question is asking for acceleration, let's first solve Newton's law
for it. Divide each side by (mass) and we have
Acceleration = (net force) / (mass) .
On Earth, the forces on the rocket are
(weight of 7.84 N down) + (blast of 12 N up) = 4.16 newtons UP (net)
Acceleration = (4.16 newtons UP) / (0.8 kg) = 5.2 m/s² UP .
On the moon, the forces on the rocket are
(weight of 1.3 N down) + (blast of 12 N up) = 10.7 newtons UP (net)
Acceleration = (10.7 newtons UP) / (0.8 kg) = 13.375 m/s² UP
Answer:
<h2>122kg</h2>
Explanation:
Using the law of conservation of momentum which states that 'the sum of momentum of bodies before collision is equal to their sum after collision. The bodies will move together with a common velocity after collision.
Momentum = Mass * Velocity
<u>Before collision;</u>
Momentum of receiver m1u1= 0 kgm/s (since the receiver is standing still)
Momentum of the tackler
m2u2 = 2.60*122 = 317.2 kgm/s
where m2 and u2 are the mass and velocity of the tacker respectively.
Sum of momentum before collision = 0+317.2 = 317.2 kgm/s
<u>After collision</u>
Momentum of the bodies = (m1+m2)v
v = their common velocity
m1 = mass of the receiver
Momentum of the bodies = (122+m1)(1.30)
Momentum of the bodies = 158.6+1.30m1
According to the law above;
317.2 = 158.6+1.30m1
317.2-158.6 = 1.30m1
158.6 = 1.30m1
m1 = 158.6/1.30
m1 = 122kg
The mas of the receiver is 122kg
