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Sholpan [36]
3 years ago
14

In the popular game "Angry Birds" (refer Figure), for the red bird to hit the green bird with their range 55.0 m, what should be

the launch angle (with respect to the horizontal) of the slingshot if the time of flight is 2.50 s? ​

Physics
1 answer:
Inga [223]3 years ago
4 0

Answer:

Explanation:

What are we to use as gravity in this imaginary world? I will ASSUME 9.81 m/s² and assume no air resistance.

horizontal velocity component

vx = 55.0/2.50 = 22 m/s

vertical initial velocity component

(12.0 - 10.0) = 0 + vy₀(2.50) + ½(-9.81)2.50²

vy₀ = 13.0625 m/s

θ = arctan(vy₀/vx) = arctan(13.0625/22) = 30.6997225... = 30.7°

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A firecracker is placed in the middle of a cluster of stationary billiard balls. The firecracker-billiard ball system sits on a
Tju [1.3M]

Momentum is one of those things that are 'conserved' (like energy). That means the total amount of momentum in an isolated system is the same after some event as it was before the event.

Before the ear-splitting explosion, while the firecracker and the billiard balls were just sitting there on the frictionless table, the momentum of the system was zero, because nothing was moving.  Right there, that tells us that the total momentum of all the balls and the fragments of the firecracker ... if you add up all the momentum vectors AFTER the explosion ... the sum is still zero. (D)

8 0
3 years ago
Read 2 more answers
A salt shaker sits 0.102 m from
Ivahew [28]

The maximum speed is 0.55 m/s

Explanation:

For an object in uniform circular motion, the force of friction between the object and the ground provides the centripetal force required to keep the body in motion. Therefore we can write:

\mu_s mg = m\frac{v^2}{r}

where the term on the left is the frictional force and the term on the right is the centripetal force, and where

\mu_s is the coefficient of static friction

m is the mass of the body

g is the gravitational acceleration

v is the speed of the body

r is the radius of the circular path

In this problem, we have:

\mu_s = 0.307

r = 0.102 m

g=9.8 m/s^2

Substituting and re-arranging, we find the maximum speed v at which the salt shaker can rotate:

v=\sqrt{\mu gr}=\sqrt{(0.307)(9.8)(0.102)}=0.55 m/s

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

#LearnwithBrainly

6 0
3 years ago
Buildings are more dense than the surrounding air. This means that they have more _____ per volume than the air and will stay on
Zinaida [17]

Answer:

<em>mass</em>

<em></em>

Explanation:

Density is the measure of how much mass of a substance is squeezed into a given volume of that substance. <em>It is the mass per unit volume</em>, and substances with lesser density will float in materials with denser density. Buildings are generally more obviously denser that air, if not we'll see then float upwards into the atmosphere, but that is not the case. Different liquids too can separate and form layers on one another due to their differences in volume.

7 0
3 years ago
Use technology and the given confidence level and sample data to find the confidence interval for the population mean muμ. Assum
Ronch [10]

Answer:

a.  μ_{95%} = 3 ± 1.8 = [1.2,4.8]

b. The correct answer is option D. No, because the sample size is large enough.

Explanation:

a. The population mean can be determined using a confidence interval which is made up of a point estimate from a given sample and the calculation error margin. Thus:

μ_{95%} = x_±(t*s)/sqrt(n)

where:

μ_{95%} = = is the 95% confidence interval estimate

x_ = mean of the sample = 3

s = standard deviation of the sample = 5.8

n = size of the sample = 41

t = the t statistic for 95% confidence and 40 (n-1) degrees of freedom = 2.021

substituting all the variable, we have:

μ_{95%} = 3 ± (2.021*5.8)/sqrt(41) = 3 ± 1.8 = [1.2,4.8]

b. The correct answer is option D. No, because the sample size is large enough.

Using the the Central Limit Theorem which states that regardless of the distribution shape of the underlying population, a sampling distribution of size which is ≥ 30 is normally distributed.

4 0
3 years ago
8.
eimsori [14]
B. Unbalanced force
3 0
3 years ago
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