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GREYUIT [131]
3 years ago
13

The energy of an object can be converted to heat due to the friction of the car on the hill. The difference between the potentia

l energy of the car and its kinetic energy at the bottom of the hill equals the energy lost due... (i need help rn lol)
Physics
1 answer:
MAVERICK [17]3 years ago
8 0

Answer:

Energy Lost for group A's car = 0.687 J

Energy Lost for group B's car = 0.55 J

Explanation:

The exact question is as follows :

Given - The energy of an object can be converted to heat due to the friction of the car on the hill. The difference between the potential energy of the car and its kinetic energy at the bottom of the hill equals the energy lost due to friction.

To find - How much energy is lost due to heat for group A's car ?

              How much for Group B's car ?

Solution -

We know that,

GPE = 1 Joule (Potential Energy)

Now,

For Group A -

Energy Lost = GPE - KE

                    = 1 J - 0.313 J

                    = 0.687 J

So,

Energy Lost for group A's car = 0.687 J

Now,

For Group B -

Energy Lost = GPE - KE

                    = 1 J - 0.45 J

                    = 0.55 J

So,

Energy Lost for group B's car = 0.55 J

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The object starts away from the origin and then moves toward the origin at a constant velocity. Next, it stops for one second. Finally, it moves away from the origin at a greater constant velocity.

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Glycerin is poured into an open U-shaped tube until the height in both sides is 20 cm. Ethyl alcohol is then poured into one arm
lina2011 [118]

Answer:

Difference in height = 7.5 cm

Explanation:

We are given;.

Height of ethyl alcohol;h2 = 20 cm = 0.2 m

Density of glycerin: ρ1 = 1260 kg/m³

Density of ethyl alcohol; ρ2 = 790 kg/m³

To get the difference in height, the pressure at the top of the open end must be equal to the pressure at the point where the liquids do not mix since both points will be at different levels after the pouring.

Thus;

P1 = P2

Formula for pressure is; P = ρgh

Thus;

ρ1 × g × h1 = ρ2 × g × h2

g will cancel out to give;

ρ1 × h1 = ρ2× h2

Making h1 the subject, we have;

h1 = (ρ2× h2)/ρ1

h1 = (790 × 0.2)/1260

h1 = 0.125 m

Difference in height will be;

Δh = h2 - h1

Δh = 0.2 - 0.125

Δh = 0.075 m = 7.5 cm

4 0
3 years ago
The speed of a 500 g cricket ball changes from 10m/s to 30m/s in just 7 seconds. What is the force acting on the cart?
9966 [12]

The force acting on the cart is 1.43 N.

<h3>What is force?</h3>

Force can be defined as the product of mass and acceleration.

To calculate the force acting on the cart, we use the formula below.

Formula:

  • F = m(v-u)/t................. Equation 1

Where:

  • F = Force acting on the cart
  • m = mass of the cart
  • v = Final velocity
  • u = initial velocity
  • t = time

From the question,

Given:

  • m = 500 g = 0.5 kg
  • v = 30 m/s
  • u = 10 m/s
  • t = 7 seconds

Substitute these values into equation 1

  • F = 0.5(30-10)/7
  • F = 10/7
  • F = 1.43 N.

Hence, the force acting on the cart is 1.43 N.

Learn more about force here: brainly.com/question/13370981

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Explanation:

Distance = speed × time

d = (27 m/s) (2.0 s)

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