All categories

3 years ago

Rob has a piece of rope that is 126 inches long he cuts the roping to 8 inch pieces how much rope does Rob have left over

1 answer:

7 0

.75 inches i think because if you divide the total by 8, it gives you 15.75 so there would be 15 eight inch pieces and a left over of .75 in.

You might be interested in

Cory earns 52.50 in 7 hours. find the unit rate

faust18 [17]

divide the two:

52.50 / 7 = 7.50 per hour

6 0

3 years ago

Read 2 more answers

Adrian has 75 coins consisting of quarters and dimes. The combined value of the coins is $10.20. How many of each type of coin d

Sergio [31]

Answer:

40 quarters and 2 dimes

Step-by-step explanation:

I did .25 (the amount of a quarter) and put it into a calculator adding.25 untill I got to 10 and then just 2 dimes bc 10+10 is 20

6 0

2 years ago

Someone pls help me with this im new thats why tysm if you do help!!:)

Kipish [7]

Answer:

-8 hope this helps

Step-by-step explanation:

7 0

3 years ago

I need help to solve the problem

natta225 [31]

Since all triangles equal 180 degrees. You will subtract (128 + 23) from 180.

180 - 146 is 34 degrees.

x=34

8 0

3 years ago

Read 2 more answers

Suppose that two openings on an appellate court bench are to be filled from current municipal court judges. The municipal court

Ksju [112]

Answer:

$(a)\dfrac{92}{117}$

$(b)\dfrac{8}{39}$

$(c)\dfrac{25}{117}$

Step-by-step explanation:

Number of Men, n(M)=24

Number of Women, n(W)=3

Total Sample, n(S)=24+3=27

Since you cannot appoint the same person twice, the probabilities are <u>without replacement.</u>

(a)Probability that both appointees are men.

$P(MM)=\dfrac{24}{27}X \dfrac{23}{26}=\dfrac{552}{702}\\=\dfrac{92}{117}$

(b)Probability that one man and one woman are appointed.

To find the probability that one man and one woman are appointed, this could happen in two ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.

P(One man and one woman are appointed) $=P(MW)+P(WM)$

$=(\dfrac{24}{27}X \dfrac{3}{26})+(\dfrac{3}{27}X \dfrac{24}{26})\\=\dfrac{72}{702}+\dfrac{72}{702}\\=\dfrac{144}{702}\\=\dfrac{8}{39}$

(c)Probability that at least one woman is appointed.

The probability that at least one woman is appointed can occur in three ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.
Two women are appointed

P(at least one woman is appointed) $=P(MW)+P(WM)+P(WW)$

$P(WW)=\dfrac{3}{27}X \dfrac{2}{26}=\dfrac{6}{702}$

In Part B, $P(MW)+P(WM)=\frac{8}{39}$

Therefore:

$P(MW)+P(WM)+P(WW)=\dfrac{8}{39}+\dfrac{6}{702}\\$P(at least one woman is appointed)=\dfrac{25}{117}$

5 0

3 years ago