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2 years ago

What is the length of this rectangle?

Mathematics

2 answers:

solong [7]2 years ago

6 0

Answer:

long

Step-by-step explanation:

well, as you can clearly see this is certainly not a short rectangle. maybe a little stocky, but certainly not short. also, I'm not very good at math, so dont ask me.

Yakvenalex [24]2 years ago

5 0

Answer and Step-by-step explanation:

The answer is:

$x^3 - 3$

When we multiply this length by the height ( $8x^{2}$ ), we get the area.

When a power/exponent (attached to a base/number) is having its' base being multiplied to another base with an exponent (and the bases are the same), the exponents will add together.

<u><em>#teamtrees #PAW (Plant And Water)</em></u>

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Use linear approximation to approximate √25.3 as follows.

Sophie [7]

The idea is to use the tangent line to $f(x)=\sqrt x$ at $x=25$ in order to approximate $f(25.3)=\sqrt{25.3}$ .

We have

$f(x)=\sqrt x\implies f(25)=\sqrt{25}=5$

$f'(x)=\dfrac1{2\sqrt x}\implies f'(25)=\dfrac1{10}$

so the linear approximation to $f(x)$ is

$L(x)=f(5)+f'(5)(x-5)=5+\dfrac{x-5}{10}=\dfrac x{10}+\dfrac92$

Hence $m=\frac1{10}$ and $b=\frac92$ .

Then

$f(25.3)\approx L(25.3)=\dfrac{25.3}{10}+\dfrac92=\boxed{7.03}$

4 0

2 years ago

Help I’ll mark you brainly!

Gnesinka [82]

Pls mark brainleist

7 0

2 years ago

Georgia’s scores in six subjects are 89, 75, 92, 68, 78, 75, and 80. If she finds a single value that summarizes all the values

Kruka [31]

Answer:

mean

Step-by-step explanation:

mean .

mean is regarded as the average value calculated from a data set .

mean = total sum of values / total number of values.

8 0

2 years ago

Which function is undefined for x = 0? y=3√x-2 y=√x-2 y=3√x+2 y=√x=2

Andre45 [30]

For this case, we must indicate which of the given functions is not defined for $x = 0$

By definition, we know that:

$f (x) = \sqrt {x}$ has a domain from 0 to infinity.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.

Thus, we observe that:

$y = \sqrt {x-2}$ is not defined, the term inside the root is negative when $x = 0$ .

While $y = \sqrt {x + 2}$ if it is defined for $x = 0.$

$f(x)=\sqrt[3]{x}$ , your domain is given by all real numbers.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root.

So, we have:

$y = \sqrt [3] {x-2}$ with x = 0: $y = \sqrt [3] {- 2}$ is defined.

$y = \sqrt [3] {x + 2}$ with x = 0: $y = \sqrt [3] {2}$ in the same way is defined.

Answer:

$y = \sqrt {x-2}$

Option b

6 0

2 years ago

X and y are positive integers. explain why incorrect to claim that

dedylja [7]

You can find counterexamples to disprove this claim. We have positive integers that are perfect square numbers; when we take the square root of those numbers, we get an integer.

For example, the square root of 1 is 1, which is an integer. So if y = 1, then the denominator becomes an integer and thus we get a quotient of two integers (since x is also defined to be an integer), the definition of a rational number.

Example: x = 2, y = 1 ends up with $\frac{2}{\sqrt{1}} = \frac{2}{1}$ which is rational. This goes against the claim that $x/\sqrt{y}$ is always irrational for positive integers x and y.

Any integer y that is a perfect square will work to disprove this claim, e.g. y = 1, y = 4, y= 9, y = 16. So it is not always irrational.

4 0

2 years ago