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ICE Princess25 [194]
3 years ago
5

What is the length of this rectangle?

Mathematics
2 answers:
solong [7]3 years ago
6 0

Answer:

long

Step-by-step explanation:

well, as you can clearly see this is certainly not a short rectangle. maybe a little stocky, but certainly not short. also, I'm not very good at math, so dont ask me.

Yakvenalex [24]3 years ago
5 0

Answer and Step-by-step explanation:

The answer is:

x^3 - 3

When we multiply this length by the height (8x^{2}), we get the area.

When a power/exponent (attached to a base/number) is having its' base being multiplied to another base with an exponent (and the bases are the same), the exponents will add together.

<u><em>#teamtrees #PAW (Plant And Water)</em></u>

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Order the numbers from least to greatest -1/3, -0.3, 4/3, 1.2, 3/2
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Answer:

1/3,-0.3,1.2,4/3,3/2

Step-by-step explanation:

-1/3,-0.3,1.2,4/3,3/2

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3 years ago
Ricardo S. gave 158 baseball cards to Ayden and 45 cards to Conner. He had 42 cards left. how many baseball cards did Ricardo S.
Inessa05 [86]

Answer:

203 ;  245

Step-by-step explanation:

158 + 45= 203

question 2

203+42= 245

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Step-by-step explanation:

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-1/9 + (-5/9) =<br><br> Write the answer in simplest form
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A small regional carrier accepted 19 reservations for a particular flight with 17 seats. 14 reservations went to regular custome
Ludmilka [50]

Answer:

(a) The probability of overbooking is 0.2135.

(b) The probability that the flight has empty seats is 0.4625.

Step-by-step explanation:

Let the random variable <em>X</em> represent the number of passengers showing up for the flight.

It is provided that a small regional carrier accepted 19 reservations for a particular flight with 17 seats.

Of the 17 seats, 14 reservations went to regular customers who will arrive for the flight.

Number of reservations = 19

Regular customers = 14

Seats available = 17 - 14 = 3

Remaining reservations, n = 19 - 14 = 5

P (A remaining passenger will arrive), <em>p</em> = 0.52

The random variable <em>X</em> thus follows a Binomial distribution with parameters <em>n</em> = 5 and <em>p</em> = 0.52.

(1)

Compute the probability of overbooking  as follows:

P (Overbooking occurs) = P(More than 3 shows up for the flight)

                                        =P(X>3)\\\\={5\choose 4}(0.52)^{4}(1-0.52)^{5-4}+{5\choose 5}(0.52)^{5}(1-0.52)^{5-5}\\\\=0.175478784+0.0380204032\\\\=0.2134991872\\\\\approx 0.2135

Thus, the probability of overbooking is 0.2135.

(2)

Compute the probability that the flight has empty seats as follows:

P (The flight has empty seats) = P (Less than 3 shows up for the flight)

=P(X

Thus, the probability that the flight has empty seats is 0.4625.

4 0
3 years ago
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