Answer:
The fourth term of the expansion is -220 * x^9 * y^3
Step-by-step explanation:
Question:
Find the fourth term in (x-y)^12
Solution:
Notation: "n choose k", or combination of k objects from n objects,
C(n,k) = n! / ( k! (n-k)! )
For example, C(12,4) = 12! / (4! 8!) = 495
Using the binomial expansion formula
(a+b)^n
= C(n,0)a^n + C(n,1)a^(n-1)b + C(n,2)a^(n-2)b^2 + C(n,3)a^(n-3)b^3 + C(n,4)a^(n-4)b^4 +....+C(n,n)b^n
For (x-y)^12, n=12, k=3, a=x, b=-y, and the fourth term is
C(n,3)a^(n-3)b^3
=C(12,3) * x^(12-3) * (-y)^(3)
= 220*x^9*(-y)^3
= -220 * x^9 * y^3
Answer:
Y=5x
Step-by-step explanation:
The first the options aren’t even whole numbers
Answer:
<em>( - 1 , - 4 ) </em>
Step-by-step explanation:
y = 3x - 1
y = x - 3
3x - 1 = x - 3 ⇒ <u><em>x = - 1</em></u>
y = 3( - 1 ) - 1 = - 4
<u><em>y = - 4</em></u>
<em>( - 1 , - 4 )</em>
Answer:44y=44y
Step-by-step explanation: combine the like terms of 32y and 12y and u get 44y=44y which cant be simplified further
