All categories

3 years ago

What is the length of this rectangle?

Mathematics

2 answers:

solong [7]3 years ago

6 0

Answer:

long

Step-by-step explanation:

well, as you can clearly see this is certainly not a short rectangle. maybe a little stocky, but certainly not short. also, I'm not very good at math, so dont ask me.

Yakvenalex [24]3 years ago

5 0

Answer and Step-by-step explanation:

The answer is:

$x^3 - 3$

When we multiply this length by the height ( $8x^{2}$ ), we get the area.

When a power/exponent (attached to a base/number) is having its' base being multiplied to another base with an exponent (and the bases are the same), the exponents will add together.

<u><em>#teamtrees #PAW (Plant And Water)</em></u>

You might be interested in

Graph and show your work please

aleksandr82 [10.1K]

Answer:

we can't graph

Step-by-step explanation:

7 0

3 years ago

Please hurry please

Elza [17]

Answer:

C is greater than or equal to 20, so the answer is C=20

3 0

3 years ago

The key personal decisions that can influence your personal safety while exercising are __________. A. making sure to replace lo

saul85 [17]

Making sure to replace lost fluids, before, during, and after exercise.

4 0

3 years ago

Triangle ABC has vertices at A(2,3),B(-4,-3) and C(2,-3) find the coordinates of each point of concurrency.

dem82 [27]

Answer:

Circumcenter =(-1,0)

Orthocenter =(2,-3)

Step-by-step explanation:

Given : Points A = (2,3), B = (-4,-3), C = (2,-3)

Formula used :

→Mid point of two points- $(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

→Slope of two points - $\frac{y_2-y_1}{x_2-x_1})$

→Perpendicular of a line = $\frac{-1}{slope of line})$

Circumcenter- The point where the perpendicular bisectors of a triangle meets.

Orthocenter-The intersecting point for all the altitudes of the triangle.

To find out the circumcenter we have to solve any two bisector equations.

We solve for line AB and AC

So, mid point of AB = $(\frac{2-4}{2},\frac{3-3}{2})=(-1,0)$

Slope of AB = $\frac{-3-3}{-4-2}=1$

Slope of the bisector is the negative reciprocal of the given slope.

So, the slope of the perpendicular bisector = -1

Equation of AB with slope -1 and the coordinates (-1,0) is,

(y – 0) = -1(x – (-1))

y+x=-1………………(1)

Similarly, for AC

Mid point of AC = $(\frac{2+2}{2},\frac{3-3}{2})=(2,0)$

Slope of AC = $\frac{-3-3}{2-2}=\frac{-6}{0}$

Slope of the bisector is the negative reciprocal of the given slope.

So, the slope of the perpendicular bisector = 0

Equation of AC with slope 0 and the coordinates (2,0) is,

(y – 0) = 0(x – 2)

y=0 ………………(2)

By solving equation (1) and (2),

put y=0 in equation (1)

y+x=-1

0+x=-1

⇒x=-1

So the circumcenter(P)= (-1,0)

To find the orthocenter we solve the intersections of altitudes.

We solve for line AB and BC

So, mid point of AB = $(\frac{2-4}{2},\frac{3-3}{2})=(-1,0)$

Slope of AB = $\frac{-3-3}{-4-2}=1$

Slope of the bisector is the negative reciprocal of the given slope.

So, the slope of CF = -1

Equation of AB with slope -1 and the coordinates (-1,0) gives equation CF

(y – 0) = -1(x – (-1))

y+x=-1………………(3)

Similarly, mid point of BC = $(\frac{-4+2}{2},\frac{-3-3}{2})=(-1,-3)$

Slope of AB = $\frac{-3+3}{-4-2}=0$

Slope of the bisector is the negative reciprocal of the given slope.

So, the slope of AD = 0

Equation of AB with slope 0 and the coordinates (-1,-3) gives equation AD

(y-(-3)) = 0(x – (-1))

y+3=0

y=-3………………(4)

Solve equation (3) and (4),

Put y=-3 in equation (3)

y+x=-1

-3+x=-1

x=2

Therefore, orthocenter(O)= (2,-3)

7 0

3 years ago

. What are the equation and slope of the line that is parallel to the y-axis and goes through the point (1,-2)?

Brrunno [24]

The answer:

x = 1

Explanation:

If the line is parallel to the y-axis it has no slope, so you would only write down the x-intercept.

8 0

2 years ago