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Natalka [10]
3 years ago
8

100 POINTS HELP!!! Each time a tennis ball is used, its pressure is 999/1,000 what it was after the previous use

Mathematics
2 answers:
Vladimir79 [104]3 years ago
8 0

Answer:

-Exponential decay

Step-by-step explanation:

999/1000 is the multiplying factor, which means the graph is exponential

Since 999/1000 < 1, it's a decay

madam [21]3 years ago
7 0

Answer:

B

Step-by-step explanation:

Looking at the problem, we see that our constant rate is 999/1000 because the pressure is only nine hundred ninety-nine <em>hundredths</em> of the previous pressure. Since this is a rate, it can't be a linear function, so eliminate C.

Now, look at the rate. 999/1000 < 1, which means that the function is decreasing as the x values approach infinity or grow larger. That is an indication that this is an exponential <em>decay</em>.

The answer is thus B.

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Elis [28]
<span>Multiply one of the equations so that both equations share a common complementary coefficient.
       In order to solve using the elimination method, you need to have a matching coefficient that will cancel out a variable when you add the equations together. For the 2 equations given, you have a huge number of choices. I'll just mention a few of them.
   You can multiply the 1st equation by -2/5 to allow cancelling the a term.
   You can multiply the 1st equation by 5/3 to allow cancelling the b term.
   You can multiply the 2nd equation by -2.5 to allow cancelling the a term. You can multiply the 2nd equation by 3/5 to allow cancelling the b term.
   You can even multiply both equations.
For instance, multiply the 1st equation by 5 and the second by 3. And in fact, let's do that. 5a + 3b = –9 2a – 5b = –16 5*(5a + 3b = -9) = 25a + 15b = -45
   3*(2a - 5b = -16) = 6a - 15b = -48
       Then add the equations 25a + 15b = -45
   6a - 15b = -48
   =
   31a = -93
   a = -3
       And then plug in the discovered value of a into one of the original equations and solve for b.</span>
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Answer:

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Decimal Form:

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<em><u>i hope this helped at all.</u></em>

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Step-by-step explanation:

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