The dimensions of room are
. Thus, volume of room will be:
![V=(11.5\times 12\times 20.5) ft^{3}=2829 ft^{3}](https://tex.z-dn.net/?f=V%3D%2811.5%5Ctimes%2012%5Ctimes%2020.5%29%20ft%5E%7B3%7D%3D2829%20ft%5E%7B3%7D)
Converting
to ![m^{3}](https://tex.z-dn.net/?f=m%5E%7B3%7D)
Since, ![1 ft^{3}=0.02831 m^{3}](https://tex.z-dn.net/?f=1%20ft%5E%7B3%7D%3D0.02831%20m%5E%7B3%7D)
Thus, ![2829 ft^{3}=(0.02831\times 2829)m^{3}=80.08 m^{3}](https://tex.z-dn.net/?f=2829%20ft%5E%7B3%7D%3D%280.02831%5Ctimes%202829%29m%5E%7B3%7D%3D80.08%20m%5E%7B3%7D)
Now, concentration of carbon monoxide in the urban apartment is
, thus, mass of carbon monoxide can be calculated as follows:
![C=\frac{m}{V}](https://tex.z-dn.net/?f=C%3D%5Cfrac%7Bm%7D%7BV%7D)
Rearranging, ![m=C\times V](https://tex.z-dn.net/?f=m%3DC%5Ctimes%20V)
Putting the values,
![m=(48\mu g/m^{3})\times (80.08 m^{3})=3.84\times 10^{3}\mu g](https://tex.z-dn.net/?f=m%3D%2848%5Cmu%20g%2Fm%5E%7B3%7D%29%5Ctimes%20%2880.08%20m%5E%7B3%7D%29%3D3.84%5Ctimes%2010%5E%7B3%7D%5Cmu%20g)
converting ![\mu g\rightarrow g](https://tex.z-dn.net/?f=%5Cmu%20g%5Crightarrow%20g)
Since,
thus,
![3.84\times 10^{3}\mu g=3.84\times 10^{3}\times 10^{-6}=3.84\times 10^{-3}g](https://tex.z-dn.net/?f=3.84%5Ctimes%2010%5E%7B3%7D%5Cmu%20g%3D3.84%5Ctimes%2010%5E%7B3%7D%5Ctimes%2010%5E%7B-6%7D%3D3.84%5Ctimes%2010%5E%7B-3%7Dg)
Therefore, mass of carbon monoxide present in the room is
.
The liver cells produce proteins to avoid blood clotting. They also break down old or damaged blood cells.
<h3><u>Answer;</u></h3>
Covalent bonds
<h3><u>Explanation;</u></h3>
- <em><u>Sticky ends refers to the bases of DNA that are unpaired because of the action of the restriction enzymes.</u></em>
- <em><u>Sticky ends are referred to as sticky because they have complementary bases.</u></em> Sticky ends allow base pairing through covalent bonds between the bases.
- The action of restriction enzymes results to overhangs, or the so called sticky ends which allow perfect base pairing, where Adenine (A) pairs with Thyamine (T) and Guanine (G) pairs with cytosine (C), as a result of covalent bonding.
Formula: q=m*c*(change in T)
q= 418.6
m=26.86
c= X(unknown)
(Change in T)= (67.3-27.4 = 39.9)
Now you solve for X, I got .391.
So the specific heat of this certain metal is .391 j/gram C