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Triss [41]
2 years ago
13

Part 1. A lightly inflated balloon is placed in a freezer. Explain the change to the size of the balloon based on the kinetic mo

lecular theory.
Part 2. What would most likely happen to the balloon if it was instead kept outside in the sun for some time? Explain your answer based on the kinetic molecular
theory.
In both cases, assume the balloon is tied tight enough so that air does not escape.
Chemistry
1 answer:
Eduardwww [97]2 years ago
6 0

According to Kinetic molecular theory, the frozen balloon shrank and it will expands and get burst when it is kept in sun.

<h3>What is Kinetic molecular theory ?</h3>

Kinetic molecular theory of gases is a theoretical model that describes the molecular composition of the gas in terms of a large number of submicroscopic particles which include atoms and molecules.

According to this theory, gas pressure arises due to particles colliding with each other and the walls of the container.

Because the average kinetic energy of the gas molecules in a balloon decreases when the temperature decreases.

This makes the molecules move more slowly and have less frequent and weaker collisions with the inside wall of the balloon, which causes the balloon to shrink a little.

Due to the sun's heat, the kinetic energy of particles in the balloon increases and it expands and continues to expand and comes to a stage when the balloon bursts.

Therefore,

According to Kinetic molecular theory, the frozen balloon shrank and it will expands and get burst when it is kept in sun.

Learn more about kinetic theory here ;

brainly.com/question/14349214

#SPJ1

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Answer:

Mass of C₂H₄N₂ produced = 3.64 g

Explanation:

The balanced chemical equation for the reaction is given below:

3CH₄ (g) + 5CO₂ (g) + 8NH₃ (g) → 4C₂H₄N₂ (g) + 10H₂O (g)

From the equation, 3 moles of CH₄ reacts with 5 moles of CO₂ and 8 moles of NH₃ to produce 4 moles of C₂H₄N₂ and 10 moles of H₂O

Molar masses of the compounds are given below below:

CH₄ = 16 g/mol; CO₂ = 44 g/mol; NH3 = 17 g/mol; C₂H₄N₂ = 56 g/mol; H₂O g/mol

Comparing the mole ratios of the reacting masses;

CH₄ = 1.65/16 = 0.103

CO₂ = 13.5/44 = 0.307

NH₃ = 2.21/17 = 0.130

converting to whole number ratios by dividing with the smallest ratio

CH₄ = 0.103/0.103 = 1

CO₂ = 0.307/0.103 = 3

NH₃ = 0.130/0.103 = 1.3

Multiplying through with 5

CH₄ = 1 × 5 = 5

CO₂ = 3 × 5 = 15

NH₃ = 1.3 × 5 = 6.5

Therefore, the limiting reactant is NH₃

8 × 17 g (136 g) of NH₃ reacts to produce 4 × 56 g (224 g) of C₂H₄N₂

Therefore, 2.21 g of NH₃ will produce (2.21 × 224)/136 g of C₂H₄N₂ = 3.64 g of C₂H₄N₂

Mass of C₂H₄N₂ produced = 3.64 g

7 0
3 years ago
Why does water have a much higher boiling point than methane even though water (H20) and methane (CH4) molecules are approximate
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Answer:

Water has a higher boiling point because the hydrogen bonds that form water molecules are stronger than the Van der Waals interactions among methane molecules, therefor more energy must be provided in order to break the hydrogen bonds and allow the water molecules to escape the liquid state.

Explanation:

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3 years ago
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3 years ago
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1. Write the name meaning
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Answer:

A.. 0.1 gram this means 0.0001kg of the object in SI unit

b. 0.01 meter this means 1 / 10 of 1 meter of the measurement

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3 years ago
Suppose 20.8 g of sodium iodide is dissolved in 250. mL of a 0.70 M aqueous solution of silver nitrate. Calculate the final mola
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Answer:

[Ag+] = [NO3-] = 0.700M

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Explanation:

To solve this question we need to find the moles of sodium iodide, NaI, using its molar mass -. With the moles and the volume we can find the molarity of Na+ and I-. The molarity of the ions of silver nitrate, AgNO3 doesn't change because we are assuming the volume doesn't change:

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<em>Moles NaI -Molar mass: 149.89g/mol-</em>

20.8g NaI * (1mol/149.89g) = 0.0139 moles NaI

<em>Molarity:</em>

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