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Triss [41]
2 years ago
13

Part 1. A lightly inflated balloon is placed in a freezer. Explain the change to the size of the balloon based on the kinetic mo

lecular theory.
Part 2. What would most likely happen to the balloon if it was instead kept outside in the sun for some time? Explain your answer based on the kinetic molecular
theory.
In both cases, assume the balloon is tied tight enough so that air does not escape.
Chemistry
1 answer:
Eduardwww [97]2 years ago
6 0

According to Kinetic molecular theory, the frozen balloon shrank and it will expands and get burst when it is kept in sun.

<h3>What is Kinetic molecular theory ?</h3>

Kinetic molecular theory of gases is a theoretical model that describes the molecular composition of the gas in terms of a large number of submicroscopic particles which include atoms and molecules.

According to this theory, gas pressure arises due to particles colliding with each other and the walls of the container.

Because the average kinetic energy of the gas molecules in a balloon decreases when the temperature decreases.

This makes the molecules move more slowly and have less frequent and weaker collisions with the inside wall of the balloon, which causes the balloon to shrink a little.

Due to the sun's heat, the kinetic energy of particles in the balloon increases and it expands and continues to expand and comes to a stage when the balloon bursts.

Therefore,

According to Kinetic molecular theory, the frozen balloon shrank and it will expands and get burst when it is kept in sun.

Learn more about kinetic theory here ;

brainly.com/question/14349214

#SPJ1

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How many grams does 6.02 x 1023 atoms of he weight​
skelet666 [1.2K]

Answer:

=16.00 g/mole

Explanation:Oxygen’s atomic weight is 16.00 amu.

1 mole of oxygen is 6.02 x 1023 atoms of oxygen

1 amu = 1.661 x 10-24g

What is the molar mass (g/mole) of oxygen?

16.00 amu/oxygen atom x 1.661 x 10-24g/amu

= 2.657 x 10-24 g/atom x 6.02 x 1023 atoms/mole

=16.00 g/mole

Molar mass (in grams) is always equal to the atomic weight

7 0
3 years ago
4. ¿Cuál es la resistencia de un alambre de
Artemon [7]

Answer:

R=0.0438 Ω

Explicación:

1) Hallar el área o sección del conductor de cobre, usando esta fórmula:

                                      A=π.r² (Pi x radio al cuadrado)

Debido a que conocemos el diámetro (1.5mm) su radio es la mitad de esto es decir 0.75mm, y lo sustituimos en la fórmula:

                                      A=π.(0.75mm)²

                                      A=π(0.5625mm²)

                                      A=1.7671mm²

2) La resistividad del cobre es: rho = 0,0172 y la incluimos en la fórmula siguiente:

                                      R=p  

                                      R=0,0172Ω  x  

Simplificamos:

R=

El resultado es:

R=0.0438 Ω

Explanation:

5 0
3 years ago
Convert -8.0 degrees F to<br> degrees C.<br> [?]°C
Westkost [7]

Answer:

7.22 Celcius

Explanation:

You got this.

7 0
4 years ago
Read 2 more answers
Which best describes the relationships between subatomic particles in any neutral atom? * 1 point the number of electrons equals
Anna71 [15]

Atomic number = protons

Protons = P  Electrons = E     P = E

Atomic mass = Neutrons + Protons

Atomic number = atomic mass = neutrons

P = E

AM - AN = N

Example:

Calcium = 20 Protons  20P = 20E

Atomic mass - atomic number = neutrons :)

4 0
4 years ago
Suppose that you lowered the temperature of a gas from 100˚C to 50 ˚C. By what factor do you change the volume of the gas?
Maru [420]

Answer:- Volume decreases by a factor of 1.15.

Solution:- At constant pressure, volume of the gas is directly proportional to the the kelvin temperature.

The equation is written as:

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where, V_1 is the volume at initial temperature T_1 and V_2 is the volume at final temperature T_2 .

Temperature must be in kelvins. So, let's convert both the temperatures to kelvin.

To convert degree C to kelvin we add 273.

So, T_1  = 100 + 273 = 373 K

T_2 = 50 + 273 = 323 K

The equation could also be written as:-

\frac{V_1}{V_2}=\frac{T_1}{T_2}

\frac{V_1}{V_2}=\frac{373}{323}

\frac{V_1}{V_2} = 1.15

From here we could say that the volume decreases by a factor of 1.15.

For example if the initial volume V_1 is 1 L then final volume V_2 will be \frac{1L}{1.15} that is 0.87 L.




4 0
3 years ago
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