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Lorico [155]
2 years ago
13

Mr. and Mrs. North joined a local fitness club. The club charges each member a $25.00 registration fee and a monthly membership

fee. They were billed a total of $500.00 for two 12-month memberships.
How much is the club's monthly membership fee?
Mathematics
2 answers:
DochEvi [55]2 years ago
7 0
First you subtract double the registration fee from the total and then divide by 24
You get 500-50= 450
450/24=18.75
Hope this helped
dezoksy [38]2 years ago
4 0

Answer:

$18.75

Step-by-step explanation:

Mr. and Mrs. North joined a local fitness club.

Membership registration fee = $25.00

They were billed a total 500.00 for two 12-month membership.

Monthly fee of the club = \frac{(500/2)-25}{12}

                                       = \frac{250-25}{12}

                                       = \frac{225}{12}

                                       = $18.75

Club's monthly membership fee is $18.75.

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8_murik_8 [283]

Answer:

c=

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Step-by-step explanation:

a=

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Step 1: Multiply both sides by c-d.

ac−ad=b

Step 2: Add ad to both sides.

ac−ad+ad=b+ad

ac=ad+b

Step 3: Divide both sides by a.

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6 0
2 years ago
Although cities encourage carpooling to reduce traffic congestion, most vehicles carry only one person. For example, 64% of vehi
ira [324]

Answer:

a) 0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

b) 0.996 is the probability that more than half of the vehicles  carry just one person.    

Step-by-step explanation:

We are given the following information:

A) Binomial distribution

We treat vehicle on road with one passenger as a success.

P(success) = 64% = 0.64

Then the number of vehicles follows a binomial distribution, where

P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 10

We have to evaluate:

P(x \geq 6) = P(x =6) +...+ P(x = 10) \\= \binom{10}{6}(0.64)^6(1-0.64)^4 +...+ \binom{10}{10}(0.64)^{10}(1-0.79)^0\\=0.7291

0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

B) By normal approximation

Sample size, n = 92

p = 0.64

\mu = np = 92(0.64) = 58.88

\sigma = \sqrt{np(1-p)} = \sqrt{92(0.64)(1-0.64)} = 4.60

We have to evaluate the probability that more than 47 cars carry just one person.

P(x \geq 47)

After continuity correction, we will evaluate

P( x \geq 46.5) = P( z > \displaystyle\frac{46.5 - 58.88}{4.60}) = P(z > -2.6913)

= 1 - P(z \leq -2.6913)

Calculation the value from standard normal z table, we have,  

P(x > 46.5) = 1 - 0.004 = 0.996 = 99.6\%

0.996 is the probability that more than half out of 92 vehicles carry just one person.

5 0
2 years ago
Ok her it is need help
Furkat [3]

Answer:

..........

Step-by-step explanation:

5 0
3 years ago
Write an equation of the line that has a slope of 2 and y-intercept 1 in slope-intercept form.
Vlada [557]
Y = mx + b

in this case m = 2 and b = 1 so
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4 0
3 years ago
Read 2 more answers
What is 1574/15 redused
r-ruslan [8.4K]

Answer:

104 14/15

Step-by-step explanation:

15 goes into 1574 104 times and you have 14 remaining so you have 104 with a remaining fraction of 14/15.

3 0
3 years ago
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