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grin007 [14]
3 years ago
15

Order from least to greatest 1/8,-3/16,-1/4,1/32,5/32,-1/16

Mathematics
1 answer:
jasenka [17]3 years ago
3 0

Answer

-1/4

-3/16

-1/16

1/32

1/8

5/32

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PLEASE HELP TIMEDD
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Correct answer: A) A = the card is red, B = the card is black

Because mutually exclusive means "cannot occur simultaneously."
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Solve the inequality:<br><br> 2x + 3 &gt; -11
Kruka [31]

Answer:

x > − 7

Step-by-step explanation:

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Find the area of a circle with a circumference of 31.5 units
Westkost [7]

Answer:

79 units²

Step-by-step explanation:

The area of a circle is found by using the formula A = π x r². Since we are not given the radius we can use the formula r = C / (2π). Substituting in the given values, we get r = 31.5/(2π). 2 times pi is 6.283185307. 31.5 divided by this will get you 5.013380707. Now, put that value in for r in the area equation. A = π x 5.013380707². Pi times 5.013380707² equals 78.96074613. This can be rounded to 79. (Or 80 if you need to the nearest whole number.)

6 0
3 years ago
The exponential function f<br> takes the value 10 when x=1 and 30 when x=2
BaLLatris [955]

Answer: x=2

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8 0
3 years ago
Write the point-slope form of the equation of the line that passes through the points (-3, 5) and (-1, 4). Please answer quickly
Oksanka [162]
The point-slope form of the equation of a line is

y - y_1 = m(x - x_1)

where

(x_1, y_1)

is a point on the line, and

m

is the slope of the line.

We can use either one of the two given points as the point on the line.
We also need to find the slope. We can use the coordinates of the two given points to find the slope of the line.

The slope of the line that passes through points

(x_1, y_1) and (x_2, y_2)

is

m = \dfrac{y_2 - y_1}{x_2 - x_1}

Let's find the slope using (-3, 5) as point 1 and (-1, 4) as point 2.

m = \dfrac{4 - 5}{-1 - (-3)} = \dfrac{-1}{-1 + 3} = \dfrac{-1}{2} = -\dfrac{1}{2}

Now we use the point-slope formula with point 1 and the slope we found just above.

y - y_1 = m(x - x_1)

y - 5 = -\dfrac{1}{2}(x - (-3))
4 0
3 years ago
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