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4 years ago

Suppose that 0.25 mole of gas C was added to

Chemistry

1 answer:

Juli2301 [7.4K]4 years ago

6 0

Answer:

Pi = 0.25[P(TTL)/n(TTL)]

Explanation:

Let Total Pressure = P(TTL) and Total moles =n(TTL) => n(i)/n(TTL) = P(i)/P(TTL)

Given n(i) = 0.25 => Pi = 0.25[P(TTL)/n(TTL)]

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a hydrogen fuel cell is more efficient than a combustion reaction because very little of the released energy is released as . wh

MrRissso [65]

Answer:

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3 years ago

In a laboratory experiment you are given 46.1 grams of MgSO4 and asked to make a 1.20 M solution. The volume of your solution wi

Darina [25.2K]

Answer:

0.319 L

Explanation:

M(MgSO4) = 120 g/mol

46.1 g * 1 mol/120 g = 0.384 mol MgSO4

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3 years ago

A reaction A(aq)+B(aq)↽−−⇀C(aq) has a standard free‑energy change of −4.20 kJ/mol at 25 °C. What are the concentrations of A, B,

Dafna1 [17]

Answer : The concentration of $A,B\text{ and }C$ at equilibrium are 0.132 M, 0.232 M and 0.168 M respectively.

Explanation :

The given chemical reaction is,

$A(aq)+B(aq)\rightleftharpoons C(aq)$

First we have to calculate the equilibrium constant for the reaction.

The relation between the equilibrium constant and standard free‑energy is:

$\Delta G^o=-RT \ln k$

where,

$\Delta G^o$ = standard free‑energy change = -4.20 kJ/mole

R = universal gas constant = 8.314 J/mole.K

k = equilibrium constant = ?

T = temperature = $25^oC=273+25=298K$

Now put all the given values in the above relation, we get:

$-4.20kJ/mole=-(8.314J/mole.K)\times (298K) \ln k$

$k=5.45$

Now we have to calculate the concentrations of A, B, and C at equilibrium.

The given equilibrium reaction is,

$A(aq)+B(aq)\rightleftharpoons C(aq)$

Initially 0.30 0.40 0

At equilibrium (0.30-x) (0.40-x) x

The expression of equilibrium constant will be,

$k=\frac{[C]}{[A][B]}$

$5.45=\frac{x}{(0.30-x)\times (0.40-x)}$

By solving the term x, we get

$x=0.168\text{ and }0.716$

From the values of 'x' we conclude that, x = 0.716 can not more than initial concentration. So, the value of 'x' which is equal to 0.716 is not consider.

The value of x will be, 0.168 M

The concentration of $A$ at equilibrium = (0.30-x) = 0.30 - 0.168 = 0.132 M

The concentration of $B$ at equilibrium = (0.40-x) = 0.40 - 0.168 = 0.232 M

The concentration of $C$ at equilibrium = x = 0.168 M

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4 years ago

kepler's first law explains that the sun is the focus of our solar system, and that _____. the orbit of a planet around the sun

alexgriva [62]

Kepler's first law explains that the sun is the focus of our solar system, and that A. <span>the orbit of a planet around the sun is an ellipse. Kepler proved that the orbit of the sun is an elliptical path and is used to derive the motion of the satellites and space vehicles today.</span>

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3 years ago

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Balance in basic solution: O2(g) + Cr³+ (aq) → H₂O2 (1) + Cr₂O7²- (aq)

likoan [24]

cr2o72+H2o2-(r3+o2)

Explanation:

r62o72+H2o2-(r3+o2)

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3 years ago