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3 years ago

Can alkenes react with potassium dichromate

Chemistry

1 answer:

posledela3 years ago

7 0

NO alkenes can not react with potassium dichromate

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In the reduction of 4-tert-butylcyclohexanone with sodium borohydride, the major product has the tert-butyl group in the equator

Evgen [1.6K]

Answer:

Axial position

Explanation:

In the reduction of 4-tert-butylcyclohexanone with sodium borohydride, the major product has the tert-butyl group in the equatorial position and the alcohol in the axial position.

The reason for this is that, axial bonds are parallel to each other. If substituents are larger than hydrogen, they experience a greater steric crowding in axial compared to the equatorial position. Therefore, many substituted cyclohexane compounds prefer a conformation in which the larger substituents are in equatorial position.

8 0

3 years ago

If one iron nail weighs 2.0 grams, what would be the mass of 6.022 x 10^23 nails?

Maru [420]

Answer:

$1.2x10^{24}g$

Explanation:

Hello!

In this case, it is possible to treat this problem by using a proportional factor which indicates one iron nail equals 2.0 grams:

$\frac{2.00g}{1nail}$

Now, for an amount of 6.022x10²³ nails, the corresponding mass will be:

$6.022x10^{23}nail*\frac{2.00g}{1nail} \\\\1.2x10^{24}g$

Best regards!

8 0

3 years ago

How many particles are in 6.02 moles of methane?

r-ruslan [8.4K]

One mole of methane has a mass of 16 g

5 0

3 years ago

Which of the following elements listed is the least metallic

Dominik [7]

Where's the list? It depends on which one it is. It could be Chlorine, silicon, or anything on the non metals side of the periodic table if you don't list it.

5 0

4 years ago

Calculate the number of pounds of CO2 released into the atmosphere when a 22.0 gallon tank of gasoline is burned in an automobil

IrinaK [193]

Answer:

391.28771 pounds of carbon-dioxide released into the atmosphere.

Explanation:

Density of the gasoline ,d= 0.692 g/mL

Volume of gasoline in an tanks,V = 22.0 gallons = 83,279.02 mL

Let mass of the gasolin be M

$d=\frac{M}{V}$

M = V × d = 83,279.02 mL × 0.692 g/mL=57,629.081 g

Assume that gasoline is primarily octane (given)

$2C_8H_{18}+25O_2\rightarrow 16CO_2+18H_2O$

Mass of octane burnt in the tank = M = 57,629.081 g

Moles of octane = $\frac{57,629.081 g}{114.08 g/mol}=505.1637 mol$

According to reaction, 2 moles of octane gives 16 moles of carbon-dioxide.

Then 505.1637 mol of octane will give:

$\frac{16}{2}\times 505.1637 mol=4,041.3100 mol$ of carbon-dioxide

Mass of 4,041.3100 mol of carbon-dioxide:

4,041.3100 mol × 44.01 g/mol = 177,858.05 g

Mass of carbon-dioxide produced in pounds = 391.28771 pounds

391.28771 pounds of carbon-dioxide released into the atmosphe

4 0

3 years ago