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Studentka2010 [4]
3 years ago
10

Consider the following reaction. The system is allowed to reach an equilibrium and then FeS2(s) is added. What will happen if Fe

S2 is added to the reaction? 4 FeS2(s) + 11 O2(g) ⇌ 2 Fe2O3(s) + 8 SO2(g)
Chemistry
1 answer:
AveGali [126]3 years ago
8 0

Answer:

More products (Fe2O3 and SO2) will be produced

Explanation:

In the reaction:

4 FeS2(s) + 11 O2(g) ⇌ 2 Fe2O3(s) + 8 SO2(g)

FeS2 is a reactant. When a reactant is added to a reaction which has already reached the equilibrium, more product is produced, so that the equilibrium is reestablished again

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Can a tank of oxygen gas ever be half empty? explain
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Im sorry about my answer a while ago.

answer: it will not be half empty ever. because any gas take all the space of the tank. molecules are everywhere they take so much space.
4 0
3 years ago
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Large mountain ranges rising up from the ocean floor are called
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Answer:

c mid ocean ridges

Explanation:

google def-A mid-ocean ridge or mid-oceanic ridge is an underwater mountain range, formed by plate tectonics. This uplifting of the ocean floor occurs when convection currents rise in the mantle beneath the oceanic crust and create magma where two tectonic plates meet at a divergent boundary.

a basin is like a bowl and a plain is flat.

7 0
2 years ago
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1. An oxide of chromium is found to have the following % composition: 68.4% Cr
abruzzese [7]

Answer:

Empirical formula is Cr₂O₃.

Explanation:

Given data:

Percentage of Cr = 68.4%

Percentage of O = 31.6%

Empirical formula = ?

Solution:

Number of gram atoms of Cr = 68.4 / 52 = 1.3 2

Number of gram atoms of O = 31.6 / 16 = 1.98

Atomic ratio:

                            Cr               :         O

                           1.32/1.32     :       1.98/1.32

                               1              :        1.5

Cr : O = 1 :  1.5

Cr : O = 2(1 : 1.5)

Empirical formula is Cr₂O₃.

6 0
3 years ago
Why do populations of bacteria in nature eventually stop growing
LekaFEV [45]
They run out of nutrients or supplies. such as other organisms
8 0
3 years ago
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When 3.00 g of sulfur are combined with 3.00 g of oxygen, 6.00 g of sulfur dioxide (SO2) are formed. What mass of oxygen would b
bazaltina [42]
Actually, we can answer the problem even without the first statement. All we have to do is write the reaction for the production of sulfur trioxide.

2 S + 3 O₂ → 2 SO₃

The stoichiometric calculations is as follows:

6 g S * 1 mol/32.06 g S = 0.187 mol S
Moles O₂ needed = 0.187 mol S * 3 mol O₂/2 mol S = 0.2805 mol O₂
Since the molar mas of O₂ is 32 g/mol,
Mass of O₂ needed = 0.2805 mol O₂ * 32 g/mol = 8.976 g O₂
4 0
3 years ago
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