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Tresset [83]
3 years ago
14

15 mL of a 0.16 M solution of glucose was diluted until the total volume reached 95 mL. What is the concentration of new solutio

n?
Chemistry
1 answer:
Nana76 [90]3 years ago
3 0

Answer:

the concentration of new solution = 0.025 M

Explanation:

Given that :

The initial volume V_1 = 15 mL

Initial concentration M_1 = 0.16 M

Final volume V_2 = 95 mL

Final concentration M_2 = ???

We know that M_1 × V_1 = M_2V_2

Making M_2 the subject of the formulae; we have :

M_2 = (M_1 × V_1)/V_2

M_2 = (0.16 × 15)/ 95

M_2 = 0.025 M

Thus, the concentration of new solution = 0.025 M

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The pressure of a given amount of gas is directly proportional to its absolute temperature, provided that the volume does not change (Amontons's law). ... The volume of a given amount of gas is inversely proportional to its pressure when temperature is held constant (Boyle's law).

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The table above lists the wavelength range, frequency range, possible uses, and hazards of the seven types of electromagnetic
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3 years ago
How many grams of ammonium sulfide are in 2.35 mile of ammonium sulfide
Afina-wow [57]

Answer:

160.18 grams

Explanation:

You find the molar mass which is 68.16 g/mol and multiply that by the number of moles present.

8 0
3 years ago
How many grams are in 1.11 moles of MN3(SO4)7
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7 0
3 years ago
Help Pls!!
AlexFokin [52]

The mass of carbon in 1 liter of mixture = 1.108 g

<h3>What is the mass of carbon in 1 liter of the mixture?</h3>

The mass of carbon in 1 liter of the mixture is determined as follows:

First the moles of gas is determined using the ideal gas formula:

  • n = PV/RT

n = (1 * 1)/(0.08205L * 298)

n = 0.0409 mole of total gas

mass of gas is then determined using the formula:

  • mass = density * volume

mass = 1 * 1.375

mass = 1.375 g

Let x = mass of CH₄ and y = mass of C₄H₁₀

x + y = 1.375 g

nCH₄ + nC₄H₁₀ = ntotat

moles = mass/molar mass

x + y = 1.695 => y = 1.695 - x

(x/molar mass of CH₄) + [(1.375 - x)/ molar mass C₄H₁₀ = 0.0409

x/16 + (1.375 - x)/58 = 0.0409

x = 0.380 g CH₄

y = 1.375 - 0.380

y = 0.995 g of C₄H₁₀

mass of C in CH₄ = 12/16 * 0.380 = 0.285

mass of C in C₄H₁₀ = 48/58 * 0.995 = 0.823

Mass of carbon in 1 liter of mixture = 0.285 + 0.823

Mass of carbon in 1 liter of mixture = 1.108 g

In conclusion, the carbon is the major component in the mixture.

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