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12345 [234]
3 years ago
13

Find the solution set for the system of equations. 9x + 5y = 28 5x + 9y = 56

Mathematics
1 answer:
masha68 [24]3 years ago
5 0
9x + 5y = 28 . . . . . (1)
5x + 9y = 56 . . . . . (2)

(1) x 5 => 45x + 25y = 140 . . . . . (3)
(2) x 9 => 45x + 81y = 504 . . . . . (4)

(3) - (4) => --56y = -364 => y = 6.5

From (1), 9x + 5(6.5) = 28 => 9x = 28 - 32.5 = -4.5 => x = -4.5/9 = -0.5
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What is the least common multiple (LCM) of 15 and 45? A. 15 B. 675 C. 45 D. 90
harkovskaia [24]

Answer:

C - 45 is the LCM of 15 & 45

Step-by-step explanation:

Find the multiples:

15, 30, 45, 60

45, 90

They both have 45 in common

3 0
3 years ago
Arah went to the grocery store and bought 4 loaves of bread and 1 gallon of milk for $12. The next week, Sarah bought 2 loaves o
sergejj [24]

Answer:

Here, b represents one loaf of bread and m represents the one gallon of milk.

As per the statement:

Arah went to the grocery store and bought 4 loaves of bread and 1 gallon of milk for $12.

⇒4b+m = 12  

It is also given that the next week, Sarah bought 2 loaves of bread and 3 gallons of milk for $13.50.

⇒2b+3m = 13.50

Then; system of equation :

4b+m = 12                   .....[1]

2b+3m = 13.50           .....[2]

Solve for b and m using above system of equations.

Multiply equation [2] by 2 we get;

4b+6m = 27              .....[3]

Subtract equation [1] from [3] we get;

4b+6m - 4b -m= 27-12

Combine like terms;

5m= 15

Divide both sides by 5 we get;

m = $3

Substitute the value of m in equation [1] we get;

4b+3 = 12

Subtract 3 from both sides we get;

4b=9

Divide both sides by 4 we get;

b = $2.25

Therefore, cost of one loaf of bread (b) and one gallon of milk (m) are:

$2.25 ad $3



3 0
3 years ago
Factor the trionomial x^2+15x+14
uysha [10]

Answer:(x+1)(x+14)


Step-by-step explanation:


8 0
3 years ago
What is the domain of the graph ?
marysya [2.9K]
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11-Determine the specific heat of a material if a 12-g sample absorbed 96 J as it was heated from 20°C to 40°C. *
kompoz [17]

Answer:

c=0.4\ J/g^{\circ} C

Step-by-step explanation:

Given that,

Mass of a sample, m = 12 g

Heat absobed by the sample, Q = 96 J

It was heated from 20°C to 40°C.

We need to find the specific heat of a material. The heat absorbed by a sample is given by :

Q=mc\Delta T\\\\c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{96}{12\times (40-20)}\\\\=0.4\ J/g^{\circ} C

So, the specific heat of the material is 0.4\ J/g^{\circ} C.

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3 years ago
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