Answer:
1/60 probabiliity
Step-by-step explanation:
You have two independent events that you want to put together.
Let Pr. mean "probability"
Pr(5 from 10 cards and 2 on a dice ) = Pr(5 from 10 cards) * Pr( 2 on a dice)
Pr(5 from 10 cards and 2 on a dice ) =(1/10) * (1/6)
= 1/60
Pr(5 from 10 cards and 2 on a dice ) =0.0167
or 1.67% probability
Abby has 7 more grapes because 16-9=7
The function "choose k from n", nCk, is defined as
nCk = n!/(k!*(n-k)!) . . . . . where "!" indicates the factorial
a) No position sensitivity.
The number of possibilities is the number of ways you can choose 5 players from a roster of 12.
12C5 = 12*11*10*9*8/(5*4*3*2*1) = 792
You can put 792 different teams on the floor.
b) 1 of 2 centers, 2 of 5 guards, 2 of 5 forwards.
The number of possibilities is the product of the number of ways, for each position, you can choose the required number of players from those capable of playing the position.
(2C1)*(5C2)*(5C2) = 2*10*10 = 200
You can put 200 different teams on the floor.
꙰ Hello there mohammedsaquibali45 ! My Name is ⚝Tobie⚝ and I'm glad you asked! Let me walk you step by step in order to comprehend the question better! ꙰
i
{x}^{2}-5x-10x+50
x
2
−5x−10x+50
ii Collect like terms.
{x}^{2}+(-5x-10x)+50
x
2
+(−5x−10x)+50
iii Simplify.
{x}^{2}-15x+50
x
2
−15x+50
Answer:
Step-by-step explanation:
1. binomial polynomial
2. 2 terms
3. 4 is the constant term
4. - 1/10 x^3 is the leading term
5. -1/10 is the leading coefficient.
