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GrogVix [38]
3 years ago
14

−3(x + 3) = −3(x + 1) − 5

Mathematics
1 answer:
g100num [7]3 years ago
4 0

Expand:

-3x - 9 = -3x - 3 - 5

Simplify:

-3x - 9 = -3x - 8

Add 3x to both sides:

-9 = -8

THERE IS NO VALUE FOR X THAT MAKES THIS EQUATION TRUE

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How do u solve 63=-9d?
Len [333]
-9d = 63
you divide both side by -9

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d = -7
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3 years ago
How many yards off the line of scrimmage does the pass rusher need to line up?
stich3 [128]

The pass rusher, which is typically line up on the line of scrimmage.

Have a Great Day :)

3 0
2 years ago
How do you do this question?
Ksivusya [100]

Answer:

V = (About) 22.2, Graph = First graph/Graph in the attachment

Step-by-step explanation:

Remember that in all these cases, we have a specified method to use, the washer method, disk method, and the cylindrical shell method. Keep in mind that the washer and disk method are one in the same, but I feel that the disk method is better as it avoids splitting the integral into two, and rewriting the curves. Here we will go with the disk method.

\mathrm{V\:=\:\pi \int _a^b\left(r\right)^2dy\:},\\\mathrm{V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy}

The plus 1 in '1 + 2/x' is shifting this graph up from where it is rotating, but the negative 1 is subtracting the area between the y-axis and the shaded region, so that when it's flipped around, it becomes a washer.

V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy,\\\\\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx\\=\pi \cdot \int _1^3\left(1+\frac{2}{y}\right)^2-1dy\\\\\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\= \pi \left(\int _1^3\left(1+\frac{2}{y}\right)^2dy-\int _1^31dy\right)\\\\

\int _1^3\left(1+\frac{2}{y}\right)^2dy=4\ln \left(3\right)+\frac{14}{3}, \int _1^31dy=2\\\\=> \pi \left(4\ln \left(3\right)+\frac{14}{3}-2\right)\\=> \pi \left(4\ln \left(3\right)+\frac{8}{3}\right)

Our exact solution will be V = π(4In(3) + 8/3). In decimal form it will be about 22.2 however. Try both solution if you like, but it would be better to use 22.2. Your graph will just be a plot under the curve y = 2/x, the first graph.

5 0
3 years ago
Please help w steps! asap
SSSSS [86.1K]

Answer:

(4,6)

Step-by-step explanation:

The midpoint=(\frac{5+3}{2} ,\frac{11+1}{2} )

                      =(4,6)

8 0
2 years ago
Line K has the equation 9x-4y=-5x4.
Yuki888 [10]

Answer:

y = (9/4)x + 2, given that I've assume the correct meaning of "-5x4."

Step-by-step explanation:

A parallel line has the same slope as the reference line,

The reference line is 9x-4y = -5x4, as written.  I'm not sure the 4 belongs, but I'll assume it is written correctly.  I'm not sure if the term -5x4 is meant to mean -5x^4, -20x or -20.  I'll assume -20:

9x-4y = -20

Put the equation into standard slope-intercept form:  Y = mx + b, where m is the slope and b is the y-intercept (the value of y when  x = 0).

-4y = -9x - 20

y = (9/4)x + 5

This line has a slope of (9/4).  The parallel line will have the same slope.

y = (9/4)x + b

We can find a value of b that would shift this line to include (4,7) by using this point in the equation:

y = (9/4)x + b

7 = (9/4)(4) + b

7  = 9 + b

b = 2

The equation of a line parallel to the reference line is y = (9/4)x + 2

5 0
2 years ago
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