Since, the probability of success during a single event of a geometric experiment is 0.34.
We have to find the probability of success on the 6th event.
Since it is a geometric experiment. So, when a discrete random variable 'X' is said to have a geometric distribution then it has a probability density function (p.d.f.) of the form:
P=
, where q = 1 - p
So, now
P = 
where 'p' is the probability of success and 'q' is the probability of failure and x is the number of events.
Since the probability of success (p)is 0.34
Therefore, probability of failure(q)= 1 - p
= 1 - 0.34
= 0.66
and x = 6
So, P = 
= 
= 
= 0.0425
So, the nearest tenth of a percent of probability of success on the 6th event =
4.257 %
Rounding to the nearest tenth, we get
= 4.3%
So, Option A is the correct answer.
<span>During the indicated time block of 6 PM-4 AM, the movies should go as follows:
Since the G rating movies needs to be shown during the first time block, it would be first at 6 pm until around 8 pm. The NC-17 movie would also need to be LAST and from 2 am to 4 am. That leaves 3 movies left to be shown from around 8 pm to 2 Am, which could be shown in 6 different ways. If we assigned EACH movie a title of A, B or C, you get these different showing possibilities- ABC, ACB, BAC, BCA, CAB, and CBA. Since the first and last movies never change, they would default to the first and last positions while the rest is filled in.</span>
Well if u divide 100 by 20 you'll get 5 groups of cookies and brownies
218.9 rounded (218.87 not rounded)