We are asked to evaluate the integral of the given function: ∫ 1 / x(lnx)³ dx <span>Let u = lnx, </span> <span>du / dx = 1 / x </span> <span>dx = du(x) </span> <span>∫ 1 / xu³ du(x) </span> <span>∫ 1 / u³ du </span> <span>-1 / 2u² + C </span> <span>Since u = lnx, </span> <span>-1 / 2(lnx)² + C </span> <span>-1 / 2ln²x + C</span>