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UNO [17]
2 years ago
8

write a variable for A customer went to a flower shop and bought some potting soil for $12.50 and 6 shrubs. If the total bill wa

s $71.00, how much did each shrub cost if they all cost the same?
Mathematics
1 answer:
Vladimir [108]2 years ago
6 0

Answer:

Each shrub costs $9.75 and the equation will be 12.5 + 6x = 71

Step-by-step explanation:

Given, a customer bought some potting soil for $12.5 and 6 shrubs. All the shrubs were same price. Total expense was $71.00.  

So, the equation will be:

12.5+ 6x = 71.....(i)

Here, x = price of the shrub as all the shrubs are same price.  

Solving the equation number (i),  

6x = 71-12.5

or, 6x = 58.5  

or, x = 58.5/ 6

or, x = 9.75  

So, each shrub will cost $9.75 each.

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Answer:

\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n} = 15/8

Step-by-step explanation:

The sum you are trying to understand is this.

\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n}

Remember that in general when you have a geometric series  

\sum\limits_{n = 0}^{\infty} a*r^n you have that

\sum\limits_{n = 0}^{\infty} a*r^n = \frac{a}{1-r}      and that equality is true as long as     |r| < 1.

Therefore here we have

\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n} = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{3*5} \big)^n = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{15} \big)^n        and   \big|\frac{-1}{15} \big| = \frac{1}{15} < 1

Therefore we can use the formula and

\sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{15} \big)^n =  \frac{2}{1-(-1/15)} = \frac{2}{1+1/15} = 30/16  = 15/8

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dimaraw [331]

The <u>correct answer</u> is:


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Explanation:


The variables are marked on the graph. Time is marked along the x-axis, which means it is the independent variable. Height is marked along the y-axis, which means it is the dependent variable.


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The flat areas are where the elevation does not change. This would be consistent with the hiker resting.


The steep decrease at the end shows that the elevation goes down quickly. This is consistent with the hiker climbing down a steep slope.

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