The correct answer is A<B+1
<span>245.1 and <span><span>270.9 fegw46dsefzdardg sorry </span></span></span>
Answer:

General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
<u>Algebra II</u>
- Distance Formula:

Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
Point A(3, 8)
Point B(-1, 1)
<u>Step 2: Find distance </u><em><u>d</u></em>
- Substitute in points [Distance Formula]:

- [√Radical] (Parenthesis) Subtract:

- [√Radical] Evaluate exponents:

- [√Radical] Add:

Answer:
2(d-vt)=-at^2
a=2(d-vt)/t^2
at^2=2(d-vt)
Step-by-step explanation:
Arrange the equations in the correct sequence to rewrite the formula for displacement, d = vt—1/2at^2 to find a. In the formula, d is
displacement, v is final velocity, a is acceleration, and t is time.
Given the formula for calculating the displacement of a body as shown below;
d=vt - 1/2at^2
Where,
d = displacement
v = final velocity
a = acceleration
t = time
To make acceleration(a), the subject of the formula
Subtract vt from both sides of the equation
d=vt - 1/2at^2
d - vt=vt - vt - 1/2at^2
d - vt= -1/2at^2
2(d - vt) = -at^2
Divide both sides by t^2
2(d - vt) / t^2 = -at^2 / t^2
2(d - vt) / t^2 = -a
a= -2(d - vt) / t^2
a=2(vt - d) / t^2
2(vt-d)=at^2
Answer:
v
=
−
3
±
√
6/
3
Step-by-step explanation:
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