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2 years ago

Hi, can someone please answer this math question for me, please? thanks

Mathematics

2 answers:

Alisiya [41]2 years ago

6 0

Answer:

The answer to your question is: First option

Step-by-step explanation:

Data

y = 3x + 4

A (6, 8)

Process

Find the slope

y = 3x + 4

slope = 3

Find the equation

(y - y1) = m(x - x1)

y - 8 = 3(x - 6)

y = 3x - 18

y = 3x - 18 + 8

y = 3x - 10

garri49 [273]2 years ago

5 0

The answer is the first option.

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Answer:

3/196

Step-by-step explanation:

because if 2 times 14 times 7, you will get 196 and then do 1 times 3 times 1 which equal to 3. so the answer will be 3/196

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2 years ago

Gerry is looking to buy a new car and finds one she likes for $1,000. The dealership is currently offering 15% off. How much mon

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6 0

3 years ago

Read 2 more answers

I need help with thisss

Yanka [14]

I believe the answer is 18, because 5x3=15, so we can only assume that N is 6x3=18.

5 0

3 years ago

Read 2 more answers

5x^2-2x=2<br>help plsmmm

Yuki888 [10]

Answer:

Presumably you're solving for x here? Without further information we'll assume that.

With that in mind, x is approximately equal to 0.86 and -0.46

Step-by-step explanation:

Let's start by putting it in the usual ax² + bx + c format.

$5x^2- 2x = 2\\5x^2 - 2x - 2 = 0\\$

let's solve it. First we'll multiply both sides by five, making the first term a perfect square:

$25x^2 - 10x - 10 = 0\\$

Now we'll add 11 to both sides:

$25x^2 - 10x + 1 = 11\\$

Which makes the left side a perfect square:

$(5x - 1)^2 = 11$

And now we can solve for x:

$(5x - 1)^2 = 11\\\\5x - 1 = \sqrt{11} \\\\5x = 1 + \sqrt{11}\\\\x = \frac{1 + \sqrt{11}}{5}$

Note that there's no apparent way of drawing the ± symbol when editing equations, so take that + sign as actually being ±.

That gives us two answers:

$x = \frac{1 + \sqrt{11}}{5}\\\\x \approx \frac{1 + 3.32}5\\\\x \approx \frac{4.32}5\\\\x \approx 0.86$ $x = \frac{1 - \sqrt{11}}{5}\\\\x \approx \frac{1 - 3.32}5\\\\x \approx \frac{-2.32}5\\\\x \approx -0.46$

7 0

2 years ago