What is the area of a triangle with a base of 10 and height of 4?
1 answer:
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Answer:
Step-by-step explanation:
Given function is,
This function is not defined at "x(x - 2) = 0"
Therefore, for the values of x = 0 and 2, given function is not defined.
Vertical asymptote → x = 2 [Denominator = 0]
For Horizontal asymptote →
Therefore, horizontal asymptote → y =
x-intercept,
For f(x) = 0,
Numerator of the function = 0
2x² + 6x = 0
2x(x + 3) = 0
x = -3
Therefore, x - intercept → (-3, 0)
For y-intercept,
x = 0
f(0) = 0
Therefore, graph has no y-intercept.
For holes on the graph,
Since, function is not defined at x = 0,
f(x) =
f(0) =
=
Therefore, hole on the graph →