Answer:
what's the question the pic is not clear
Step-by-step explanation:
7, HT= 
=17 cm
8, S = 1/2.AC.BC.sinC≈28,01 cm^2
9, S =1/2.SR.RT.sin R≈ 3615,7 m^2
Prove:
the area of the ABC triangles is S
sin A = BH/AB
S = 1/2 BH.AC=1/2 sinA.AB.AC=1/2*c*b*sinA
The GCF is one. I hope this helps love! :)
By <span>(x + 5/x^2 + 9x + 20) you apparently meant the following:
x+5
----------------------
x^2 + 9x + 20
and by
</span><span>(x^2-16/x-4)
x^2-16
you apparently meant ---------------
x - 4
Please use additional parentheses for clarity.
Dividing,
</span> x+5 (x-4)(x+4)
---------------------- * ---------------
x^2 + 9x + 20 x-4
Now, x^2 + 9x + 20 factors into (x+4)(x+5), so what we have now is
(x+5)(x+4)
------------------------- = 1 This is true for all x, so there are no exclusions.
(x+4)(x+5)
Answer:
so you would replace all r with 2 which is 2+q-2
then replace the q with 6 so it would be: r+6-r
combined both of these to get
2+6-2
which would equal to 6
add the 2 and the 6 to get 8
then subtract 2 to get 6
