The scuba diver's position relative to sea level after the 4.6 minutes is 5.1 ft.
Given:
A scuba diver descends in the water at a rate of 23 1/2 feet per minute for 2.6 minutes.
A scuba diver ascends at a rate of 28 feet per minute for 2 minutes after seeing a big fish.
To find :
The scuba diver's position relative to sea level after the 4.6 minutes.
Solution:
Rate of a scuba diver descending in the water for 2.6 minutes = 

Distance covered by a scuba diver in 2.6 minutes = 

Rate of a scuba diver ascending for 2 minutes = 

Distance covered by a scuba diver in 2 minutes = 

The position of scuba diver after 4.6 minutes relative to sea level:

The scuba diver's position relative to sea level after the 4.6 minutes is 5.1ft.
Learn more about ascending rate and descending rate here:
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We have y - 2 = m(x + 5), where m = (-1 - 2)/(10 + 5) = -3/15 = -1/5;
Then y - 2 = (-1/5)(x + 5);
5y - 10 = (-1)(x + 5);
5y - 10 = -x - 5;
x + 5y - 5 = 0 is the equation of the line.
1. y axis can repeat/x cannot repeat
2. Parabola symmetrically across y-axis
Answer:
Rn-222
Step-by-step explanation:
this decay takes specified step therefore Rn-222is not a decaying process
Answer:
60 miles an hour
Step-by-step explanation:
^^^^^^^^