Prove that any median in a triangle is less than the half of the triangle's perimeter.
1 answer:
See image for naming of the sides: the medians are
ab, bc, and ac; and sides are a, b, and c
Pick one median, say, ab. The following are true:
ab < a
ab < b
->
ab + ab < a + b
ab < 0.5*(a+b) | add 0.5*c to the right hand side (does not change inequality)
ab < 0.5(a+b+c) = half perimeter
so ab < half perimeter
Same argument for bc, and ac holds.
You might be interested in
Answer:
B
Step-by-step explanation:
Given
f(x) =
The denominator cannot be zero as this would make f(x) undefined.
Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non zero for this value then it is a vertical asymptote.
x + 2 = 0 ⇒ x = - 2
The equation of the vertical asymptote is x = - 2