Prove that any median in a triangle is less than the half of the triangle's perimeter.
1 answer:
See image for naming of the sides: the medians are
ab, bc, and ac; and sides are a, b, and c
Pick one median, say, ab. The following are true:
ab < a
ab < b
->
ab + ab < a + b
ab < 0.5*(a+b) | add 0.5*c to the right hand side (does not change inequality)
ab < 0.5(a+b+c) = half perimeter
so ab < half perimeter
Same argument for bc, and ac holds.
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Answer:
(4,0)
Step-by-step explanation:
The object is first at (0,0)
It is reflected across line x=-2, this means you draw the mirror line at x=-2 and count 2 equal units backwards to get the image.The image will be at ;
The image (-4,0) is then reflected on the y-axis
You know reflection on the y-axis, the y-coordinate remains the same but the x-coordinate is changed to its opposite sign.
Hence;
(- -4,0)= (4,0)
The image will move 8 units towards positive x-axis.This is the same as moving 4 units from the mirror line at (0,0) and land at (4,0)