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2 years ago

A right rectangular prism is 6.5 cm by 14 cm by 5 cm. What is the surface area of the prism?

Mathematics

2 answers:

nexus9112 [7]2 years ago

5 0

Answer:

455.

Step-by-step explanation:

irina1246 [14]2 years ago

3 0

Answer:

387

Step-by-step explanation:

Formula: $2(lw+hl+wh)$

$2(14*6.5+14*5+6.5*5) = 387$

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Morgan rewrote the expression 90 + (10 + 4.8) as (90 + 10) + 4.8. How will this change the work that is needed to evaluate the e

Archy [21]

Answer:

Answer is c

Step-by-step explanation:

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2 years ago

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Juan has 20 books to sell. He sells the books for $15 each. The amount of money Juan makes from selling booka is represented by

lana [24]

Answer:

Step-by-step explanation:

Juan has 20 books to sell. He sells the books for $15 each.

The range of the function is the set of all possible values of the dependent variable. The dependent variable here is the amount of money that is made and this amount depends on

the number of books, x sold

The amount of money Juan makes from selling books is represented by a fucntion. f(x)=15x

The maximum amount that can be made from 20 books at a rate of $15 each would be 20×15 = $300

The minimum amount that fan be made is $0 and this is when no book is sold. Let y = f(x). So the range is

0 lesser than or equal to y lesser than or equal to 300

6 0

2 years ago

Rewrite In simplest radical form x^5/6/x^1/6

Nady [450]

I assume you mean:

[x^(5/6)]/[x^(1/6)]

The rule for dividing similar bases with different exponents is:

(a^b)/(a^c)=a^(b-c)

In this case we have:

x^(5/6-1/6)

x^(4/6)

x^(2/3)

3 0

3 years ago

What does the degree of a polynomial mean?

serg [7]

__Award Brainliest if helped!

Layman : The number of the largest power

Say $x^{2} +x+3$ , Degree is 2 (X^2)
and if $x^{3} + x^{2} +x+3$ , the Degree is 3.

Technical : Largest exponent of variable.

5 0

3 years ago

Mr. Mole left his burrow and started digging his way down at a constant rate.

Art [367]

Mr. Mole's burrow was at an altitude of 6 meters below the ground.

Step-by-step explanation:

Step 1:

We need to determine the distance that Mr. Mole covers in a single minute.

To do that we divide the difference in values of altitude by the difference in the time periods.

For the first case, Mr. Mole had traveled -18 meters in 5 minutes.

We also have, he traveled -25.2 meters in 8 minutes.

Step 2:

The distance he covered in 1 minute $= \frac{-25.2-(-18)}{8-5} = \frac{-25.2+18}{3},$

$\frac{-25.2+18}{3} = \frac{-7.2}{3} = -2.4.$

So with every minute, Mr. Mole digs down an additional 2.4 meters below the surface.

To determine where Mr. Mole's burrow is we subtract the distance traveled in 5 minutes from -18.

The altitude of Mr. Mole's burrow $= -18 - 5(-2.4) = -18+12 = -6.$

So Mr. Mole's burrow was at an altitude of 6 meters below the ground i.e. -6 meters.

5 0

3 years ago

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