$180 taken away from $450 is $220. the rest i'm not quite sure because there wasn't a given price for the music.
The base will have the greatest area for a given perimeter if it is square. If the edge of the square base has length x (in feet), then the total material requirement in square feet is
.. m = x^2 +(4/x^2)*(4x)
.. m = x^2 +16/x
This will have a minimum where dm/dx = 0.
.. dm/dx = 2x -16/x^2 = 0
.. x^3 = 8 . . . . . . . . . . . . . . . multiply by x^2/2 and add 8
.. x = 2
The tank is 2 feet square and 1 ft high.
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You will note that it is half the height of a cube that has double the volume. This is the generic solution to all minimum cost open-top box problems. Actually, the costs of pairs of opposite sides are equal to each other and to the cost of the base. If material costs are not identical in all directions, that is the more generic solution.
Since the radius is the same, that means that OBA=PDE
Answer:
uhm 5?
Step-by-step explanation:
because 3 we move 1 more is 4.
and 7 we go -1 which is 6 so we have 5 in the middle so the answer is 5!