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Natalija [7]
3 years ago
10

Vladimir is walking down the street at a speed of 4 miles per hour. Write an equation for the distance in miles, d, that Vladimi

r walks over time in hours, t.
Mathematics
1 answer:
zubka84 [21]3 years ago
8 0

Answer:

d=4t

Step-by-step explanation:

We have been given that Vladimir is walking down the street at a speed of 4 miles per hour. We are asked to write an for the distance in miles, d, that Vladimir walks over time in hours, t.

We will use rate formula to solve our given problem.

\text{Speed}=\frac{\text{Distance}}{\text{Time}}

\text{Distance}=\text{Speed}\times\text{Time}

Upon substituting our given information in distance equation, we will get:

d=4\cdot t

d=4t

Therefore, the equation d=4t represents the distance that Vladimir walks over time in hours.

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if p varies inversely as a square roots of d and p equals 6 when d equals 9 find the formula connecting p and d, d when p equals
netineya [11]

Step-by-step explanation:

p=1/d

6=k/9

6×9=k

54=k

2=54/d

2×d=54

d=54/2

d=27

MARK ME BRAINLIEST!!

6 0
2 years ago
Cards are drawn, one at a time, from a standard deck; each card is replaced before the next one is drawn. Let X be the number of
steposvetlana [31]

Cards are drawn, one at a time, from a standard deck; each card is replaced before the next one is drawn. Let X be the number of draws necessary to get an ace. Find E(X) is given in the following way

Step-by-step explanation:

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  • A standard deck of cards is shuffled and one card is drawn. Find the probability that the card is a queen or an ace.

P(Q or A) = P(Q) = 4/52 or 1/13 + P(A) = 4/52 or 1/13 = 1/13 + 1/13 = 2/13

  • WITHOUT REPLACEMENT: If you draw two cards from the deck without replacement, what is the  probability that they will both be aces?

P(AA) = (4/52)(3/51) = 1/221.

  • WITHOUT REPLACEMENT: What is the probability that the second card will be an ace if the first card is a  king?

P(A|K) = 4/51 since there are four aces in the deck but only 51 cards left after the king has been  removed.

  • WITH REPLACEMENT: Find the probability of drawing three queens in a row, with replacement. We pick  a card, write down what it is, then put it back in the deck and draw again. To find the P(QQQ), we find the

probability of drawing the first queen which is 4/52.

  • The probability of drawing the second queen is also  4/52 and the third is 4/52.
  • We multiply these three individual probabilities together to get P(QQQ) =
  • P(Q)P(Q)P(Q) = (4/52)(4/52)(4/52) = .00004 which is very small but not impossible.
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5 0
2 years ago
Sum of all natural numbers from100to300 which are divisible by 4and 5 is​
My name is Ann [436]

If x is a number that is both divisible by 4 and 5, then

\begin{cases}x\equiv0\pmod4\\x\equiv0\pmod5\end{cases}

4 and 5 are coprime, so we can use the Chinese remainder theorem to solve this system and find that x=20n is a solution to the system, where n is any integer. Simply put, any multiple of 20 fits the bill.

Now, there are 11 numbers between 100 and 300 that are divisible by 20 (100, 120, 140, and so on). We have 20n=100 when n=5, so the sum we want to compute is

\displaystyle\sum_{n=5}^{15}20n=\boxed{2200}

4 0
3 years ago
$44 is 55% of what dollar amount?
melomori [17]

Answer:

im pretty sure it's $19.80

Step-by-step explanation:

(44 x 55)/100 = $24.20

44 - 24.20 = $19.80

4 0
2 years ago
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The sum of ten positive odd numbers is 20. Some numbers may repeat, find the largest number that is used in this sum.
Katyanochek1 [597]

1+1+1+1+1+1+1+1+3+9

= 20

Largest number used is 9

Must click thanks and mark brainliest

8 0
2 years ago
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