Answer:-7
Step-by-step explanation:do absolute value first and then put the negative sign
Answer:

Step-by-step explanation:





Answer:
Step-by-step explanation:
dy/dx= -(2x+3y+1)/(3x-2y+1)
Let x= X+p. and y = Y+q. then dy/dx = dy/dX.
dy/dX= -(2X+2p+3Y+3q+1)/(3X+3p-2Y-2q+1) =
dy/dX = -{2X+3Y+(2p+3q+1)}/{3X-2Y+(3p-2q+1)}
Now 2p+3q+1=0……………..(1)
3p-2q +1=0…………………………(2)
p/(3+2)=q/(3–2)=1/(-4–9)
There is no picture, but you would substitute the first number for the x and the second for the y
Answer:
i don't know, i just want to know if you got it right
Step-by-step explanation: