Given:
A line passes through (1,-2) and is perpendicular to 
.
To find:
The equation of that line.
Solution:
We have, equation of perpendicular line.
Slope of this line is
Product of slope of two perpendicular lines is -1.
Now, slope of required line is 
and it passes through (1,-2). So, the equation of line is
where, m is slope.
Therefore, the equation of required line is .
Answer:
Step-by-step explanation:
12a)To rationalize the denominator, multiply the denominator and numerator by √5.
b) (a+b)² = a² + 2ab + b²
(1 +√3)² = 1² + 2*1*√3 + (√3)²
= 1 + 2√3 + 3
= 4 + 2√3
a = 4 ; b =2
13) (a + b)(a - b) = a² - b²
Answer:
(x - 8)(x + 3)
Step-by-step explanation:
x² - 5x - 24
Consider the factors of - 24 which sum to give the coefficient of the x- term (- 5)
The factors are - 8 and + 3 , since
- 8 × + 3 = - 24 and - 8 + 3 = - 5
Use these factors to split the x- term
x² - 8x + 3x - 24 ( factor the first/second and third/fourth terms )
= x(x - 8) + 3(x - 8) ← factor out (x - 8) from each term
= (x - 8)(x + 3) ← in factored form
Click on the second choice, the 3x one
In order to solve this inequality, we can do the following steps:
[tex]\begin{gathered} 45<9(x+3)<153\\ \\ \frac{45}{9}Therefore
the correct option is B.
