Answer:
A. 8.66 feet
B. 12.59 feet
C. Area of triangle when
is 129.9 square feet. Area of triangle when
is 188.85 square feet. Increasing the angle
increases the area.
Step-by-step explanation:
The equation that models the height of the triangle is:

Where,
is the height, and
is the angle
A.
When
, the height is:

B. When ![\theta=40[/tex\ , the height is:[tex]y=15Tan40\\y=12.59](https://tex.z-dn.net/?f=%5Ctheta%3D40%5B%2Ftex%5C%20%2C%20the%20%3Cstrong%3Eheight%3C%2Fstrong%3E%20is%3A%3C%2Fp%3E%3Cp%3E%5Btex%5Dy%3D15Tan40%5C%5Cy%3D12.59)
C. <em>To find the area of the isosceles triangular shaped garden, we use the </em><em>formula for the area of the triangle</em><em>:</em>

Where,
- A is the area
- b is the base, which is given as 30 feet, and
- h is the height [8.66 feet when the angle is 30 & 12.59 when angle is 40]
<u>When Vance uses
, the area is</u>:
square feet
<u>When Vance uses
, the area is</u>:
square feet
So we see that when the angle is more, the area is also more.
Answer:
8 square units and
square units
Step-by-step explanation:
The area of the triangle ABC is 24 square units.
1. Triangles ABC and FBG are similar with scale factor
then

2. Triangles ABC and DBE are similar with scale factor
then

3. Thus, the area of the quadrilateral DFGE is

and the area of the quadrilateral ADEC is

The three numbers are 12, 18 and 24
Arithmetic progression
Let the 3 number in arithmetic progression be:
a-d, d, a+d ...
If their sum is 3, then;
a-d+d+a+d = 3
2a + d = 3 ........... 1
If the sum of their squares is 11, then;
(a-d)² + d² + (a+d)² = 11
a²-2ad+d²+d²+a²+2ad+d² 11
2a²+3d² = 11 ....... 2
Solving the equations simultaneously, d = 6 and a = 12
First-term = 12
second term = 18
Thirs term = 24
Hence the three numbers are 12, 18 and 24
Hope this helps you!!!!!! :D
The missing fraction would be

since it is exactly in the halfway between
Answer:
The solutions are 3 and -5
Step-by-step explanation:
x+3=x^2+3x-12
x^2+2x-15
=(x-3)(x+5)