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Amanda [17]
3 years ago
11

One year ago, a man was 8 times as old as his son. Now his age is equal to the square of his sons age. The present age of son is

Mathematics
1 answer:
Svetlanka [38]3 years ago
3 0

Answer:

The present age of son is 7

Step-by-step explanation:

Let the son age be x

One year ago

Son's age = x - 1

Therefore man's age = 8(x-1) =8x - 8

Now man's age = x^2

Difference between both ages if man =1 years

So

x^2 -(8x-8) = 1

x^2-8x + 8-1 =0

x^2- 8x + 7 = 0

x^2 - 7x -x + 7 = 0

X(x-7) - 7 ( x - 7) = 0

(x - 1) ( x - 7) = 0

x = 1, 7

But son cannot be 1 years

Therefore ,

x = 7

SO,

age of son is <em>7</em>

age of father is x×7=<em>49</em>

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