Answer:
C) $10,000 invested at 6.7% compounded quarterly over 7 years yields the greater return.
Step-by-step explanation:
-We determine the effective interest rate in both scenarios and use it to calculate the investment's value after 7 years.
#Given n=7yrs, P=$10,000 and i=6.6% compounded monthly:
![i_m=(1+i/m)^m-1\\\\=(1+0.066/12)^{12}-1=0.06803\\\\\therefore A=P(1+i_m)^n\\\\=10000(1.06803)^7\\\\\approx \$15,852.00](https://tex.z-dn.net/?f=i_m%3D%281%2Bi%2Fm%29%5Em-1%5C%5C%5C%5C%3D%281%2B0.066%2F12%29%5E%7B12%7D-1%3D0.06803%5C%5C%5C%5C%5Ctherefore%20A%3DP%281%2Bi_m%29%5En%5C%5C%5C%5C%3D10000%281.06803%29%5E7%5C%5C%5C%5C%5Capprox%20%5C%2415%2C852.00)
#Given n=7rs, P=10000, i=6.7%
![i_m=(1+i/m)^m-1\\\\=(1+0.067/4)^{4}-1=0.06870\\\\\therefore A=P(1+i_m)^n\\\\=10000(1.06870)^7\\\\\approx \$15,921.75](https://tex.z-dn.net/?f=i_m%3D%281%2Bi%2Fm%29%5Em-1%5C%5C%5C%5C%3D%281%2B0.067%2F4%29%5E%7B4%7D-1%3D0.06870%5C%5C%5C%5C%5Ctherefore%20A%3DP%281%2Bi_m%29%5En%5C%5C%5C%5C%3D10000%281.06870%29%5E7%5C%5C%5C%5C%5Capprox%20%5C%2415%2C921.75)
Hence, the investment has the largest value($15,921.75) when the interest rate is compounded quarterly.
The total of how many pieces you have
A) c + t = 60
B) 3c = 7t
Multiplying A) by -3
A) -3c + -3t = -180 then adding this to b
B) 3c = 7t
180 = 10t
trucks = 18
cars = 42
Answer:
35
Step-by-step explanation:
70 × 0.5 = 35
or
50% = 1/2
so
70/2 = 35
Answer:
total number of students is 25
AIZA AND GLAIZA came 60% of the 25 students that is 15th position
A) therefore students which came below them were= 10
B) Students who has scored greater than them were=> 15-2=13 (as they niether got less than 12 nor more than 12.)