4 years ago

Use properties to find sum or product of 4 + (6+21)

1 answer:

4 0

You need to use pemdas so first you do inside the parenthesis 6+21=27 then you add 4 27+4=31 that is your answer

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gogolik [260]

Answer:

When x=8, y=-6. When x=10, y=0

Step-by-step explanation:

$y=3x-30\\x^2+y^2=100$

You can plug the given y value into the second equation to get:

$x^2+(3x-30)^2=100\\x^2+9x^2-180x+900=100\\10x^2-180x+800=0\\10(x^2-18x+80)=0\\10(x-8)(x+10)=0\\x= 8, 10\\y= -6, 0$

Hope this helps!

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VMariaS [17]

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I am Lyosha [343]

Answer:

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Step-by-step explanation:

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3 years ago