We can solve this by using the formula:
(x, y) (x + a, y + b) = (5,-4) (-2,1)
So, plugging in the values and solving for a and b,
5 + a = -2
a = -8
-4 + b = 1
b = 5
Therefore, the translation is
(x,y) (x - 8, y +5)
Answer:
2000 L
Step-by-step explanation:
There are 1250 L of water in a tank at present. If the tank is 0.625 full, what is the capacity of the tank?
The simple solution is:
1250 L ÷ 0.625 = 2000 L
The algebraic solution is:
Let <em>c</em> equal the capacity of the tank.
Therefore, <em>c</em> × 0.625 = 1250.
Divide both sides by 0.625:
<em>c</em> × 0.625 ÷ 0.625 = 1250 ÷ 0.625
And simplify:
<em>c</em> = 1250 ÷ 0.625
<em>c</em> = 2000
Answer:
Answers are below in bold
Step-by-step explanation:
1) A = 1/2bh Use this equation to find the area of each triangular base
A = 1/2(8)(6) Multiply
A = 1/2(48) Multiply
A = 12cm² Area of each triangular base
2) A = L x W Use this equation to find the area of the bottom rectangular face
A = 20 x 8 Multiply
A = 160 cm² Area of the bottom rectangular face
3) A = L x W Use this equation to find the area of the back rectangular face
A = 20 x 6 Multiply
A = 120 cm² Area of the back rectangular face
4) A = L x W Use this equation to find the area of the sloped rectangular face
A = 20 x 10 Multiply
A = 200 cm² Area of the sloped rectangular face
5) To find the total surface area of the triangular prism, add together all of the numbers.
A = 12 + 12 + 160 + 120 + 200 Add
A = 504 cm² Total area of the triangular prism
One worker<span> produces an average of 84 units per </span>day<span> with a street </span>What is the probability<span> that in any </span>single day worker 1 will outproduce worker 2<span>? A) 0.1141.
</span>
Answer, factory worker productivity<span> is </span>normally distributed<span>. </span>One worker produces<span> an </span>average<span> of 75 </span>units per day<span> with a standar, day with a </span>standard deviation<span> of 20. </span>Another worker produces<span> at an </span>average rate<span> of 65 </span><span>per day.
</span>
A perfect fifth above a note has a frequency ratio of 3 to 2.
Therefore, we can set the proportion:
164.81 : x = 2 : 3
which gives:
x = <span>164.81 </span>× 3 ÷ 2
= 247.21
Hence, the perfect fifth above E₃ will have a frequency of 247.21Hz which corresponds to a B₃.
