Subtract 5p + 8q from the sum of 5p + 4q and – 9p + 69.

Mathematics

2 answers:

givi [52]3 years ago

6 0

Answer: -9p - 4q + 69

Explanation:

(5p + 4q + (-9)p + 69) - (5p + 8q)
= 5p + 4q - 9p + 69 - 5p - 8q
= -9p - 4q + 69

Mice21 [21]3 years ago

4 0

Answer:

-9p -4q + 69

Step-by-step explanation:

5p +4q + (-9p +69)

=> 5p + 4q -9p +69

=> -4p +4q +69

Now, we need to subtract 5p +8q from -4p + 4q +69

=> -4p +4q +69 - (5p +8q)

=> -4p + 4q +69 - 5p -8q

=> -9p -4q + 69

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JulsSmile [24]

Answer:

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Step-by-step explanation:

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You find 72 coins consisting only of nickels, dimes, and quarters, with a face value of $10.20. However, the coins all date from

Oliga [24]

Answer:

You have found 24 nickels.

Step-by-step explanation:

Let N be the number of nickles, D be the number of dimes and Q be the number of quarters. The number of coins and their face values are given by the following expressions, respectively:

$N+D+Q=72\\0.05N+0.10D+0.25Q=10.20$

As of now we have three variables and two expressions, the final expression needed to solve the linear system is given by the amount offered by the coin dealer:

$10N+20D+15Q=1,060$

Solving the linear system:

$N+D+Q=72\\5N+10D+25Q=1,020\\10N+20D+15Q=1,060\\\\10N-10N+20D-20D+15Q-50Q=1,060-(2*1,020)\\-35Q=-980\\Q=28\\\\5N-10N+10D-10D+25Q-10Q=1,020-720\\-5N+15Q=300\\-5N=300-(15*28)\\N=24$