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maksim [4K]
2 years ago
12

Can you help me with 10 and 11... thank you

Mathematics
2 answers:
Sauron [17]2 years ago
8 0
The sum of the intereior angles for a regular polygon with n side is 180(n-2)

so pentaon is 5 sides, n=5
180(5-2)=180(3)=540 degrees
the sum of it's interior angles is 540 degrees



11.
draw diagram

we gotss a right triangle

remember, for any right triangle if the legs are a and b and hytponuse is c then
a²+b²=c²
hypotnuse is longest side
in this case, hytponuse is the diagonal

teh legs are 40 and 24
the hypotnuse is the diagonal

40²+24²=c²
1600+576=c²
2176=c²
sqrt both sides
8√34=c
aprox
c≈46.64
rounded
c=46.6ft

anzhelika [568]2 years ago
3 0
10. Because a pentagon has 5 sides and the sum of all the interior angles of a shape is 360 degrees, you would divide 360 by 5, to get the measure of each interior angle inside the shape. 360/5=72, therefore each interior angle would have a measure of 72 degrees.

11. To find the length of the diagonal of Davey's log cabin, you can use the Pythagorean Theorem, using 40 and 24 as a and b. You would have to solve the equation 40 squared + 24 squared = c squared, were c would represent the length you are finding. If you solve the equation, you find that the length of the diagonal of Davey's Cabin is 46.6 ft.
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It takes a train 60 seconds to completely drive through a bridge of 1260 m, and 90 seconds to completely drive through a tunnel
Olegator [25]

The length of train is 120 meters

The speed of train is 25 meter per second

<u><em>Solution:</em></u>

The speed is given by formula:

speed = \frac{distance}{time}

Given that,

It takes a train 60 seconds to completely drive through a bridge of 1260 m

And 90 seconds to completely drive through a tunnel of 2010 m

Let the length of the train be "x"

<em><u>The total distance travelled by the train across the bridge is given by:</u></em>

total distance = x + 1260 + x = 2x + 1260

[ here we use x + x to represent that train completely drives through bridge ]

The time taken is given as 60 seconds

<em><u>Therefore, the speed is given as:</u></em>

speed = \frac{2x+ 1260}{60}

<em><u>The total distance travelled by the train through the tunnel is given by:</u></em>

total distance = x + 2010 + x = 2x + 2010

The time taken is given as 90 seconds

<em><u>Therefore, the speed is given as:</u></em>

speed = \frac{2x+ 2010}{90}

The speed of the train was the same in both cases.

Equate both speeds

\frac{2x+ 1260}{60} = \frac{2x+ 2010}{90}

\frac{x+630}{30} = \frac{x+1005}{45}

45(x+630) = 30(x+1005)\\\\45x + 28350 = 30x + 30150\\\\45x - 30x = 30150 - 28350\\\\15x = 1800\\\\x = 120

Thus length of train is 120 meters

<em><u>Find the speed of train:</u></em>

speed = \frac{2x+ 1260}{60}\\\\speed = \frac{2(120) + 1260)}{60}\\\\speed = 25

Thus speed of train is 25 meter per second

5 0
3 years ago
Express it in slope-intercept form.
natka813 [3]

Hey there! :)

Answer:

y = 1/4x - 3.

Step-by-step explanation:

Use the slope-formula to find the slope of the line:

m = \frac{\text{rise}}{\text{run}} = \frac{y_2 - y_1}{x_2 - x_1}

Plug in two points from the line. Use the points (-4, -4) and (0, 3):

m  = \frac{-3 - (-4)}{0 - (-4)}

Simplify:

m = 1/4.

Slope-intercept form is y = mx + b.

Find the 'b' value by finding the y-value at which the graph intersects the y-axis. This is at y = -3. Therefore, the equation is:

y = 1/4x - 3.

7 0
2 years ago
Find the missing dimension of the cylinder. Round your answer to the<br> nearest tenth.
vekshin1

Answer:

10ft

Step-by-step explanation:

volume= 502ft³

or, πr²h = 502 ft³

or, h= 502/ (4²π)

or, h= 9.98~10ft

6 0
2 years ago
Is this graph continuous at x=1?
drek231 [11]

Answer:

Step-by-step explanation:

By my definition, no. There's a continuity up to and including just before 1 approaching from the left, and there's a continuity just after 1 going to the right. But 1 itself has a special definition h(x) = 4 when x = 1 and that makes it discontinuous.

8 0
3 years ago
Can somebody help with this math homework
Lelu [443]

Whats the math you need help with?

4 0
2 years ago
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