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KATRIN_1 [288]
3 years ago
13

1-25. Given f(x) =- 2/3x +3 and g(x) = 2x2 - 5, complete parts (a) through (f).

Mathematics
1 answer:
Korolek [52]3 years ago
3 0

Answer:

When f or g are equivalent to a number you are solving for x. For example b, d, e, f. In the equation g(x) =2x2-5 I assumed 2 was a typo. So, if it's incorrect, please use same steps and just adjust the solution.

Step-by-step explanation:

f(x)=-\frac{2}{3x}+3

a) f(3)=-\frac{2}{2(3)} +3

           =-\frac{1}{3}+3 =\frac{-1+6}{3} =\frac{5}{3}

b) f(x)=-5

      -5=-\frac{2}{3x}+3

      -8=-\frac{2}{3x}

  -24x=-2

        x=\frac{1}{12}

g(x)=2x-5

c) g(-3)=2(-3)-5

               =-6-5

               =-11

d) g(x)=-7

      -7=2x-5

      -2=2x

        x=-1

e) g(x)=8

        8=2x-5

       12=2x

        x=6

f)  g(x)=9

         9=2x-5

        11=2x

         x=\frac{11}{2}

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Answer:

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Step-by-step explanation:

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A= (pi)(8a^6)^2

A = (pi)64a^12

A = 64pia^12

5 0
2 years ago
Julia is taking a test with multiple choice and true/false question the test has twentg question altogether . julia gets five po
Sonbull [250]
X=number of corect
y=number of incorrect
5 points for each correct so 5x
-1 point for each incorrect so -y

5x-y=76
solve for x and y

I like putting it into slope intercep tofrm which is y=mx+b
add y to both sides
5x=76+y
subtract 76 from both sides
5x-75=y
y=5x-76

subsitute values for x and get values for y
remember, that julia cannot answer a negative number of incorrect questions so y must be greater than or equal to 0

so solve for minimum
0<u><</u>5x-76
add 76 to both sides
76<u><</u>5x
divide by 5
15.2<u><</u>x
you cannot answer a fraction of a correct quesiton so round up
16 is the minumum number of queswtions correctlyh answered


so
x<u>></u>16

subsitute 16 for x
y=5(16)-76
y=80-76
y=4

as we subsitute more numbers over 16, we get these points
so (x,y) 
(16,4)
(17,9)
(18,14)
(19,19)
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(21,29)
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3 years ago
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Answer:

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3 0
3 years ago
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The limit of the expression as x approaches -3 is -24

<h3>How to determine the limit of the expression?</h3>

The expression is given as:

x^3 + 3x^2 + 4x - 12

As x approaches -3.

The limit expression becomes

\lim_{x \to -3} x^3 + 3x^2 + 4x - 12

Substitute -3 for x in the expression

\lim_{x \to -3} (-3)^3 + 3(-3)^2 - 4*3 - 12

Evaluate the expression

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