The width of the aquarium is 0.1625 ft.
Step-by-step explanation:
Given,
The length (l) of the aquarium = 2 ft
Height (h) = 1.5 ft
The capacity of water it holds = 3.75 gallons
That means the volume (V) = 3.75 gallon
To find the width(b) of the aquarium.
Formula
- The volume of a cuboid with l as length, b as width and h as height = lbh
So,
V = 3.75×0.13 cube ft
According to the problem,
2×1.5×b = 3.75×0.13
or, b = (3.75×0.13)÷(2×1.5)
or, b = 0.1625 ft
Hence,
The width of the aquarium is 0.1625 ft.
Answer:400
Step-by-step explanation: if everyone hand shakes every other person the answer will be 400, because 20 times 20 is 400
hope I helped.
The answer is 1/7 in exact form
Problem 1)
The base of the exponential is 12 which is also the base of the log as well. The only answer choice that has this is choice B.
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Problem 2)
log(x) + log(y) - 2log(z)
log(x) + log(y) - log(z^2)
log(x*y) - log(z^2)
log[(x*y)/(z^2)]
Answer is choice D
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Problem 3)
log[21/(x^2)]
log(21) - log(x^2)
log(21) - 2*log(x)
This matches with choice B
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Problem 4)
Ln(63) = Ln(z) + Ln(7)
Ln(63)-Ln(7) = Ln(z)
Ln(63/7) = Ln(z)
Ln(9) = Ln(z)
z = 9
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Problem 5)
Ln(5x-3) = 2
5x-3 = e^2
5x = e^2+3
x = (e^2+3)/5
This means choice A is the answer
Answer:
you basically do the same things just backwards
Step-by-step explanation:
for example 9+9=18 well to double check your work all you do is flip to equation 18-9=9
