Answer:
The pressure of N₂ gas in cylinder B when compressed at constant temperature increases due to the increase in the frequency of collision between the gas molecules with themselves and with the wall of their container caused by a decrease in volume of the container.
Explanation:
Gas helps to explain the behavior of gases when one or more of either temperature, volume or pressure is varying while the other variables are kept constant.
In the gas cylinder B, the temperature of the given mass of gas is kept constant, however, the volume is decreased by pushing the movable piston farther into the cylinder. According to the gas law by Robert Boyle, the volume of a given mass of gas is inversely proportional to its pressure at constant temperature. This increase in pressure is due to the increase in the frequency of collision between the gas molecules with themselves and with the wall of their container caused by a decrease in volume of the container. As the cylinder becomes smaller, the gas molecules which were spread out further become more packed closely together, therefore, their frequency of collision increases building up pressure in the process.
Answer:
The value of equilibrium constant is 29.45.
Explanation:
Moles of hydrogen gas = 2.00 mol
Concentration of hydrogen gas =
Moles of iodine gas = 1.00 mol
Concentration of iodine gas =
initially
2.00 M 1.00 M 1.00 M
At equilibrium:
(2.00-x/2) (1.00-x/2) x
Moles of HI at equilibrium = 1.80 M
Concentration of HI at equilibrium =
The expression of an equilibrium constant is given by ;
Putting x equal to 1.80 M.
The value of equilibrium constant is 29.45.
Explanation:
Phases of Matter
Question Answer
Vaporization that occurs at and below the surface of a liquid boiling
A solid that is made up of crystals in which particles are arranged in a regular, repeating pattern crystalline solid
A solid made up of particles that are not arranged in a regular pattern amorphous solid
Answer:
940 J
Explanation:
This is a calorimtetry excersie where you apply the formula
Q = C . m . ΔT
We only have 2 data from here, C and ΔT (from the solution)
C → 3.97 J/g°C
ΔT → 2.3°C
We determine the solution's mass by density:
1.03 g/mL = Solution mass / Solution volume
We assume the HCl as the solution volume → 100 mL
1.03 g/mL . 100 mL = 103 g → solution's mass
We replace data: Q = 103 g . 3.97 J/g°C . 2.3°C → 940.4 J