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Andrei [34K]
3 years ago
11

Cylinder A and Cylinder B are sealed, rigid cylinders with movable pistons. Each cylinder contains 500. milliliters of a gas sam

ple at 101.3 kPa and 298 K. Cylinder A contains H2 and cylinder B contains N2. Explain, in terms of collisions between gas molecules and the walls of the container, why pushing the movable piston farther into cylinder B at constant temperature would increase the pressure of the N2 gas.
Chemistry
1 answer:
Romashka-Z-Leto [24]3 years ago
5 0

Answer:

The pressure of N₂ gas in cylinder B when compressed at constant temperature increases due to the increase in the frequency of collision between the gas molecules with themselves and with the wall of their container caused by a decrease in volume of the container.

Explanation:

Gas helps to explain the behavior of gases when one or more of either temperature, volume or pressure is varying while the other variables are kept constant.

In the gas cylinder B, the temperature of the given mass of gas is kept constant, however, the volume is decreased by pushing the movable piston farther into the cylinder. According to the  gas law by Robert Boyle, the volume of a given mass of gas is inversely proportional to its pressure at constant temperature. This increase in pressure is due to the increase in the frequency of collision between the gas molecules with themselves and with the wall of their container caused by a decrease in volume of the container. As the cylinder becomes smaller, the gas molecules which were spread out further become more packed closely together, therefore, their frequency of collision increases building up pressure in the process.

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3 years ago
What is a solution that has the capacity to hold additional solute at a given temperature called? A. Unsaturated 
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How many grams of CO2 are produced when 6.55 of Fe2O with an excess of CO?
Anettt [7]

Answer:

the answer is fe20 Hope this helps!

Explanation:

5 0
2 years ago
PLZ HELP!!!!!!!!!!!!!
gregori [183]

117.22 g are needed to react with an excess of Fe2O3 to produce 156.2 g of Fe.

Explanation:

                  Moles of Fe = Mass of Fe in grams / Atomic weight of Fe

                                        = 156.2 / 55.847

                  Moles of Fe  = 2.79.

The ratio between CO and Fe id 3 : 2.

                  Moles CO needed  = 2.79 * (3 / 2)

                                                   = 4.185.

 To calculate Atomic weight of CO,

                  Atomic weight of carbon = 12.011

                  Atomic weight of oxygen= 15.9994

        Atomic weight of CO = 12.011 + 15.9994 = 28.01 g / mol.

                 Mass of CO   = 4.185 * 28.01 = 117.22 g.      

5 0
3 years ago
Explain the steps for naming an oxy-acid (refernce pg. 252)
nata0808 [166]

Answer:

The first element is always named first, using entire element name.

Second element is named using its root and adding the suffix -ide.

Prefixes are used to indicate the number of atoms of each element that are present in the compound.

Explanation:

8 0
3 years ago
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