Student Z completes his/her calibration step for part 3 and finds an average massA to be 95.237 g ± 0.005 g. However, in his/her

Question

3 years ago

8

Student Z completes his/her calibration step for part 3 and finds an average massA to be 95.237 g ± 0.005 g. However, in his/her

calculations, s/he mistakenly uses 85.237 g ± 0.005 g for massA. S/he uses the correct values for massB and masscyl. Will the calculated mass of displaced water be too high, too low, or unchanged? And why?

Chemistry

2 answers:

Troyanec [42] · Answer 1 · 2021-12-27T09:23:15+03:00

Troyanec [42]3 years ago

7 0

It is going to be too low because the mass mistakenly used is lower than the initial.

cupoosta [38] · Answer 2 · 2021-12-27T10:48:08+03:00

Answer:- Calculated mass of displaced water would be too low.

Explanations:- Mass of water displaced is directly proportional to the mass of the object dropped into water.

Since the average mass of A used for calculations is low than the actual mass, the calculated mass of displaced water would also be low.