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ad-work [718]
2 years ago
6

Convert 2 ounces perminute to gallons perhour.​

Mathematics
1 answer:
LenaWriter [7]2 years ago
8 0

Answer: 2 ounces per minute= 0.9375 gallons per hour

Step-by-step explanation:

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(ONLY TWO CAPITAL LETTERS) PLEASE ANSWER CORRECTLY!!!!!! WILL MARK BRIANLIEST!!!!!!!! URGENT
lesantik [10]

Answer:

HN congruent to NL

Step-by-step explanation:

They have a line crossing both of them, signifiying congruence.

6 0
3 years ago
When a distribution is mound-shaped symmetrical, what is the general relationship among the values of the mean, median, and mode
yuradex [85]

Answer:

The mean, median, and mode are approximately equal.

Step-by-step explanation:

The mean, median, and mode are <em>central tendency measures</em> in a distribution. That is, they are measures that correspond to a value that represents, roughly speaking, "the center" of the data distribution.

In the case of a <em>normal distribution</em>, these measures are located at the same point (i.e., mean = median = mode) and the values for this type of distribution are symmetrically distributed above and below the mean (mean = median = mode).

When a <em>distribution is not symmetrical</em>, we say it is <em>skewed</em>. The skewness is a measure of the <em>asymmetry</em> of the distribution. In this case, <em>the mean, median and mode are not the same</em>, and we have different possibilities as the mentioned in the question: the mean is less than the median and the mode (<em>negative skew</em>), or greater than them (<em>positive skew</em>), or approximately equal than the median but much greater than the mode (a variation of a <em>positive skew</em> case).  

In the case of the normal distribution, the skewness is 0 (zero).

Therefore, in the case of a <em>mound-shaped symmetrical distribution</em>, it resembles the <em>normal distribution</em> and, as a result, it has similar characteristics for the mean, the median, and the mode, that is, <em>they are all approximately equal</em>. So, <em>the </em><em>general</em><em> relationship among the values for these central tendency measures is that they are all approximately equal for mound-shaped symmetrical distributions, </em>considering they have similar characteristics of the <em>normal distribution</em>, which is also a mound-shaped symmetrical distribution (as well as the t-student distribution).

5 0
2 years ago
A study shows that 70 out of 200 college students read the newspaper. Marysville College has 12,600 students.
Lubov Fominskaja [6]
Your answer would be 4,410
5 0
3 years ago
Read 2 more answers
Factor the expression f^2+10f+16
denis-greek [22]

Answer: (f + 2) (f + 8)

It's hard to explain, but I suggest you use the AC method. Hope this helps!

4 0
3 years ago
Read 2 more answers
Dina planted a six-foot tree in her backyard which she expects to grow at the rate of 4 feet per year. Find the equation of the
Scrat [10]

Answer:

y = 6 + 4x

After 4 years, the tree would be 22 ft tall.

Step-by-step explanation:

Hi there!

Let x = the number of years that pass

Let y = the height of the tree (ft)

We're given that the 6-foot tree grows at a rate of 4 ft per year. This means that the height of the tree will be equal to 6 ft, the original height, plus another 4 ft every year that passes.

Height of tree = 6 feet + 4 feet × number of years that pass

y = 6 + 4x

To solve for how tall the tree would be 4 years after Dina plants it, replace x with 4, since 4 years have passed:

y = 6 + 4(4)

y = 6 + 16

y = 22

Therefore, the tree would be 22 ft tall.

I hope this helps!

8 0
2 years ago
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