1/2x+12x=5 how do u solve it
2 answers:
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Answer:
D: {(-5, -4, 2, 2, 5)}
R: {(-6, 3, 4, 1, 5)}
The relation is NOT a function.
Step-by-step explanation:
By definition:
A relation is any set of ordered pairs, which can be thought of as (input, output).
A function is a <em><u>relation</u></em> in which no two ordered pairs have the same first component (domain/input/x value) and different second components (range/output/y value).
Looking at the given points in your graph, and in listing down the domain and range, we can infer that the relation is not a function because there is an x-value (2) that has two corresponding y-values: (2, 4) (2, 1).
Another way to tell if a given set of points in a graph represents a function by doing the "Vertical line test." The graph of an equation represents y as a function of x if and only if no vertical line intersects the graph more than once. Looking at the attached image, I drew a vertical line over points (2, 4) (2, 1). The vertical line intersects the two points, which fails the vertical line test. This is an indication that the given relation is not a function.
Answer:
A) The vertex ( h , k) = ( -2 , -18)
B) The minimum value of the given function = - 18
C) The Axis of the symmetry for f(t) is y -axis
Step-by-step explanation:
A)
Given a parabola f(t) = t² + 4 t − 14
f(t) = t² + 2(2) t + (2)²-4− 14
f(t) = (t +2)² - 18
Let comparing y = (x +2)² -18
(x +2)² = y + 18
(x-h))² = 4 a ( y - k))²
<em>The vertex ( h , k) = ( -2 , -18)</em>
B)
Given a parabola f(t) = t² + 4 t − 14
Differentiating with respective to 't'
f¹(t) = 2 t + 4
f¹(t) = 2 t + 4 = 0
now
Again Differentiating with respective to 't'
f(x) has a minimum value at t = -2
Given f(t) = t² + 4 t − 14
f( -2) = 4 + 4(-2) -14 = 4 -8 -14 = -18
The minimum value of the given function = - 18
C)
f(t) = (t +2)² - 18
Let comparing y = (x +2)² -18
(x +2)² = y + 18
(x-h))² = 4 a ( y - k))²
The vertex ( h , k) = ( -2 , -18)
The Axis of the symmetry for f(t) is y -axis