y = x + 2
y = -3x
Do y = -3x in y = x + 2
y = x + 2
-3x = x + 2
-3x - x = 2
-4x = 2
x = -2/4
x = -1/2
Now put x = -1/2 in y = -3x
y = -3x
y = -3.(-1/2)
y = 3/2
0.8 squares shaded out of 10
You just do 4x2 which is 8
Then add the 0. In front of 8
Easy as that
If C is the MIDPOINT of BD, and BD equals 12, then what does CD equal?
AD = AC+CD, so you only need to find length of CD and add length of AC (which you already have) to it.
Hope this helps
Pythagoras Theorem:
hipotenuse²=leg₁²+leg₂²
First posible triangle:
hypotenuse=13 (13²=169)
leg₁=12 ( 12²=144)
leg₂=5 (5²=25)
13³=144 + 25
Answer:can be side lengths of a triangle
Second triangle:
hypotenuse=12.6 (12.6²=158.76)
leg₁=6.7 ( 6.7²=44.89)
leg₂=6.5 (6.5²=42.25)
leg₁²+leg₂²=44.89+42.25=87.14≠158.76
Answer: cannot be side lenghts of a triangle.
third triangle:
hypotenuse=13 (13²=169)
leg₁=12 ( 12²=144)
leg₂=11 (11²=121)
leg₁²+leg₂²=144+121=265≠169
Answer: cannot be side lenghts of a triangle.
fourth triangle:
hypotenuse=13 (13²=169)
leg₁=6 ( 6²=36)
leg₂=4 (4²=16)
leg₁²+leg₁²=36+16=52≠169
Answer: cannot be side lenghts of a triangle.
Answer:
(1,5)
Step-by-step explanation:
You use the midpoint formula to solve this problem
The midpoint formula:
To solve for x: (x1+x2)÷2
To solve for y: (y1+y2)÷2
