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2 years ago

True or false: equilateral triangles can be classified as acute right or obtuse

1 answer:

8 0

False, since all sides are equal all angles must be equal and when you have an obtuse or right triangle only on angle is obtuse or right. since one is different it cannot be equal on all sides making this statement false

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Matt's change of weight is 62 pounds

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Mrs.Henry hires a local moving company to help her move into her new apartment. The price includes a 15% tip. Mrs.Henry's total

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2 years ago

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2 years ago

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How can I find a rule in a math question

NeTakaya

Answer:

Step-by-step explanation:

How to write the rule of a function given the table of values. To write the rule of a function from the table is somehow tricky but can be made easier by having prior knowledge of the type of function. If the function is a linear function, plugging any two sets of values from the table into the equation y = ax + b, where a and b are constants to be found and x, y are values taken from the table. Solving the two equations obtained simultaneously gives the values of a and b and hence the required rule.

Similarly, if the function is a quadratic equation, plugging any three sets of values from the table into the equation y = ax^2 + bx + c, where a, b, c are constants to be found and x, y are values taken from the table. Solving the three equations obtained simultaneously gives the values of a, b and c and hence the required rule. For tables with no prior knowledge of the type of function, a series of trial and error will lead us to the solution of the problem.

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2 years ago

If x+y = 1, and x^2 + y^2 = -1, what is x^7 + y^13? 1) 0 2) 1 3) -2 4) 2 5) -1

damaskus [11]

Solve for x and y :

x + y = 1 → y = 1 - x

x ² + y ² = -1

x ² + (1 - x)² = -1

x ² + (1 - 2x + x ²) = -1

2x ² - 2x + 1 = -1

2x ² - 2x + 2 = 0

x ² - x + 1 = 0

x ² - x + 1/4 = -3/4

(x - 1/2)² = -3/4

x - 1/2 = ±√(-3/4)

x - 1/2 = ±√3/2 i

x = 1/2 ± √3/2 i → x = exp(± iπ/3)

y = 1 - (1/2 ± √3/2 i ) → y = -1/2 ± √3/2 i → y = exp(± 2iπ/3)

Then

x ⁷ + y ¹³ = exp(± 7iπ/3) + exp(± 26iπ/3)

… = exp(± iπ/3) + exp(± 2iπ/3)

since 7π/3 is equivalent to π/3, and 26π/3 is equivalent to 2π/3 (both modulo 2π).

In either case, we get

x ⁷ + y ¹³ = x + y = 1

so the answer is (2) 1.

8 0

2 years ago