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Dmitrij [34]
3 years ago
5

You start at (4, 5). You move down 9 units. Where do you end?

Mathematics
2 answers:
Alexxandr [17]3 years ago
8 0

Answer:

y=-x+9 so its 4,4 pls mark brainlest :(

Step-by-step explanation:

Marizza181 [45]3 years ago
4 0

Answer: 4, -4

Step-by-step explanation:

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Dylan opened a credit card account with $750.00 of available credit. Now that he has made some purchases, Dylan's account only h
barxatty [35]

Answer:

45%

Step-by-step explanation:

The formula to work out the decrease is:

Percentage Decrease= actual decrease / original amount X 100%

1) So firstly, we have to work out the decrease, to do this we have to do is do $750-$412.50= $337.50

2) We can now substitute this into our formula which will now be. (We will also add the original amount, which is $750.00)

Percentage Decrease= 337.50 / 750.00 X 100% = 45

The percentage decrease is 45%

8 0
3 years ago
• The total rise of a set of stairs is 81.125". If there are 11 risers, what is the height of
patriot [66]

Answer:

7.375".

Step-by-step explanation:

That would be 81.125 / 11

= 7.375 ".

3 0
2 years ago
Determine the location and values of the absolute maximum and absolute minimum for given function : f(x)=(‐x+2)4,where 0<×&lt
brilliants [131]

Answer:

Where 0 < x < 3

The location of the local minimum, is (2, 0)

The location of the local maximum is at (0, 16)

Step-by-step explanation:

The given function is f(x) = (x + 2)⁴

The range of the minimum = 0 < x < 3

At a local minimum/maximum values, we have;

f'(x) = \dfrac{(-x + 2)^4}{dx}  = -4 \cdot (-x + 2)^3 = 0

∴ (-x + 2)³ = 0

x = 2

f''(x) = \dfrac{ -4 \cdot (-x + 2)^3}{dx}  = -12 \cdot (-x + 2)^2

When x = 2, f''(2) = -12×(-2 + 2)² = 0 which gives a local minimum at x = 2

We have, f(2) = (-2 + 2)⁴ = 0

The location of the local minimum, is (2, 0)

Given that the minimum of the function is at x = 2, and the function is (-x + 2)⁴, the absolute local maximum will be at the maximum value of (-x + 2) for 0 < x < 3

When x = 0, -x + 2 = 0 + 2 = 2

Similarly, we have;

-x + 2 = 1, when x = 1

-x + 2 = 0, when x = 2

-x + 2 = -1, when x = 3

Therefore, the maximum value of -x + 2, is at x = 0 and the maximum value of the function where 0 < x < 3, is (0 + 2)⁴ = 16

The location of the local maximum is at (0, 16).

5 0
3 years ago
Prefixes, roots, and suffixes are examples of _____
mojhsa [17]

Answer:

The correct answer should be : Word parts

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What is the diffrence between 6 thirty-sixes and 4 thirty-sixes.?
Lilit [14]
6 thirty-sixes -4 thirty-sixes = 2 thirty-sixes
2 thirty-sixes = 2•36 = 72
6 0
3 years ago
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