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madreJ [45]
3 years ago
14

PLEASE HELP ME WITH THIS THANK U

Mathematics
2 answers:
larisa86 [58]3 years ago
4 0
It's C and D because of the fact that in y=ab^x, a is the initial value. C is correct because we know that Expression A is decaying, and the 'x' is terms of months - not years.
galina1969 [7]3 years ago
3 0
1. false
2.false
3.true
4.true
5.not sure , but i think it false
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Eva8 [605]

Answer:15*(x-3)^2*(x-5)

Step-by-step explanation:

\dfrac{x^2-y^2}{x^2-8x+15}\ and\ \dfrac{y^2}{15(x^2-6x+9)} \\\\\\x^2-8x+15=x^2-3x-5x+15=x(x-3)-5(x-3)=(x-3)(x-5)\\\\15(x^2-6x+9)=15*(x-3)^2\\\\LCM (x^2-8x+15,15(x^2-6x+9)\\\\=LCM((x-3)(x-5),15(x-3)^2)\\\\\boxed{=15*(x-3)^2*(x-5)}\\

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Answer: a= -3 or a= -11/3 ( The best answer is -11/3; if you want one)

Step-by-step explanation:

See the attachments below!

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Step-by-step explanation:

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KonstantinChe [14]

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The term "of" can be translated to multiplication in problems like this.

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